Question

the sum of 2 numbers is 56.twice the smaller number exceeds one-half the larger number by 22.find the numbers

Answer 1

Answer:

the numbers are 18 and 38

Step-by-step explanation:

x =smaller integer and y =larger integer

Answer 2

9514 1404 393Answer:

  20, 36

Step-by-step explanation:

Let x and y represent the smaller and larger numbers, respectively. The given relations let us write two equations:

  x + y = 56 . . . . . . the sum of the two numbers is 56

  2x -y/2 = 22 . . . . twice the smaller exceeds half the larger by 22

We can solve this by multiplying the second equation by 2 and adding the first.

  2(2x -y/2) +(x +y) = 2(22) +56

  5x = 100 . . . . . . simplify

  x = 20

  y = 56 -20 = 36

The two numbers are 20 and 36.