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3 years ago

8

Why does a triangular prism and an oblique triangular prism, each made up of 15 equal cross sections, have the same volume? Sele

ct all that apply.

1 answer:

statuscvo [17]3 years ago

8 0

Answer:

-The cross section areas are all the same

-The prism has the same height and area of the base

Step-by-step explanation:

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Suppose a population consists of 50,000 people. Which of the following

Bogdan [553]

Answer:

The number that would represent a sample statistic of a population but not a parameter is:

O A. Neither 500 nor 50,000

Step-by-step explanation:

The reason behind this is that a parameter has to follow a certain guideline because it needs to fulfill a rule to be considered one. There has to be a correlation, so if we have no clear establishment the number can't be a parameter. Thus, 500 would be the minimum 1% to be considered as a parameter and 50,000 the whole universe of the population. They keep a correlation, therefore any number but they would be a sample statistic.

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3 years ago

What value of x makes the function {(1,5), (x,8), (-7,9)} a function?

mestny [16]

X can be anything you want as long as it is not 1 or -7. If you have repeated x values with different y values, then it won't be a function.

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3 years ago

Tan(arcsin(x)) and its domain ...?

Mandarinka [93]

$- \frac{\pi}{2} < \arcsin{x} < \frac{\pi}{2} 
\\
\\\sin(- \frac{\pi}{2}) < \sin(\arcsin{x}) < \sin(\frac{\pi}{2} )
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\\-1 < x < 1$

6 0

3 years ago

Among persons donating blood to a clinic, 85% have Rh+ blood (that is, the Rhesus factor is present in their blood.) Six people

Leona [35]

Answer:

a) There is a 62.29% probability that at least one of the five does not have the Rh factor.

b) There is a 22.36% probability that at most four of the six have Rh+ blood.

c) There need to be at least 8 people to have the probability of obtaining blood from at least six Rh+ donors over 0.95.

Step-by-step explanation:

For each person donating blood, there are only two possible outcomes. Either they have Rh+ blood, or they do not. This means that we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$p = 0.85, n = 6$ .

a) fine the probability that at least one of the five does not have the Rh factor.

Either all six have the factor, or at least one of them do not. The sum of the probabilities of these events is decimal 1. So:

$P(X < 6) + P(X = 6) = 1$

$P(X < 6) = 1 - P(X = 6)$

In which:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 6) = C_{6,6}.(0.85)^{6}.(0.15)^{0} = 0.3771$

So

$P(X < 6) = 1 - P(X = 6) = 1 - 0.3771 = 0.6229$

There is a 62.29% probability that at least one of the five does not have the Rh factor.

b) find the probability that at most four of the six have Rh+ blood.

Either more than four have Rh+ blood, or at most four have. So

$P(X \leq 4) + P(X > 4) = 1$

$P(X \leq 4) = 1 - P(X > 4)$

In which

$P(X > 4) = P(X = 5) + P(X = 6)$

$P(X = 5) = C_{6,5}.(0.85)^{5}.(0.15)^{1} = 0.3993$

$P(X = 6) = C_{6,6}.(0.85)^{6}.(0.15)^{0} = 0.3771$

$P(X > 4) = P(X = 5) + P(X = 6) = 0.3993 + 0.3771 = 0.7764$

$P(X \leq 4) = 1 - P(X > 4) = 1 - 0.7764 = 0.2236$

There is a 22.36% probability that at most four of the six have Rh+ blood.

c) The clinic needs six Rh+ donors on a certain day. How many people must donate blood to have the probability of obtaining blood from at least six Rh+ donors over 0.95?

With 6 donors:

$P(X = 6) = C_{6,6}.(0.85)^{6}.(0.15)^{0} = 0.3771$

37.71% probability of obtaining blood from at least six Rh+ donors over 0.95.

With 7 donors:

$P(X = 6) = C_{7,6}.(0.85)^{6}.(0.15)^{1} = 0.3960$

0.3771 + 0.3960 = 0.7764 = 77.64% probability of obtaining blood from at least six Rh+ donors over 0.95.

With 8 donors

$P(X = 6) = C_{8,6}.(0.85)^{6}.(0.15)^{2} = 0.2376$

0.3771 + 0.3960 + 0.2376 = 1.01 = 101% probability of obtaining blood from at least six Rh+ donors over 0.95.

There need to be at least 8 people to have the probability of obtaining blood from at least six Rh+ donors over 0.95.

5 0

2 years ago

What is 2/5 divided by 9

Paraphin [41]

2/45 or 0.0444....
Hope this helped

3 0

3 years ago