Two solids cones geometrically similar and the height of one cone is 1 1/2 times that of the other. Given that the height of the
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we know that
m∠SQR+x= -------> by supplementary angles
so
m∠SQR=
The sum of the internal angles of a triangle is equal to degrees
m∠SQR+m∠QSR+m∠SRQ=
substitute the values in the formula
m∠SQR++
=
m∠SQR= degrees
<u>Find the value of x</u>
m∠SQR=
x=-m∠SQR
x=
x= degrees
therefore
<u>the answer is</u>
the value of x is degrees