Answer:
3/11 = 6/22
Step-by-step explanation:
3*2=6.
so 11*2 = 22
The original price was $25.
First, convert the 30% to a real mathematical number. For percents, this is always done by dividing the 30% by 100%, or 30% / 100% = 0.300.
Second, find out what 30% of $25 is. This is the amount of the sale discount. This is always found by mulitplying 0.300 by the item's cost $25, like this:
0.300 x $25 = $ 7.50.
So for this sale, you'll save $ 7.50 on this item.
This means, the cost of the item to you is
<span>$25 - $ 7.50 = $17.50.</span>
A) 2 units
B) yes
For A) |5-3|=|2|=2 is the distance from his house to school.
For B)
The distance from his house to school is 2 units; the distance from school to the grocery store is |3--9|=|12|=12. The total distance is 2+12 = 14.
The distance from his house to school is 2 units; the distance from school to the community center is |-4-6|=|-10|=10. The total distance is 2+10 = 12.
The distance from the house to the school to the grocery store is greater.
Binomial distribution formula: P(x) = (n k) p^k * (1 - p)^n - k
a) Probability that four parts are defective = 0.01374
P(4 defective) = (25 4) (0.04)^4 * (0.96)^21
P(4 defective) = 0.01374
b) Probability that at least one part is defective = 0.6396
Find the probability that 0 parts are defective and subtract that probability from 1.
P(0 defective) = (25 0) (0.04)^0 * (0.96)^25
P(0 defective) = 0.3604
1 - 0.3604 = 0.6396
c) Probability that 25 parts are defective = approximately 0
P(25 defective) = (25 25) (0.04)^25 * (0.96)^0
P(25 defective) = approximately 0
d) Probability that at most 1 part is defective = 0.7358
Find the probability that 0 and 1 parts are defective and add them together.
P(0 defective) = 0.3604 (from above)
P(1 defective) = (25 1) (0.04)^1 * (0.96)^24
P(1 defective) = 0.3754
P(at most 1 defective) = 0.3604 + 0.3754 = 0.7358
e) Mean = 1 | Standard Deviation = 0.9798
mean = n * p
mean = 25 * 0.04 = 1
stdev = 
stdev =
= 0.9798
Hope this helps!! :)
Answer:
x = 5
Step-by-step explanation:
<u>__________________________________________________________</u>
<u>FACTS TO KNOW BEFORE SOLVING</u> :-
- In an equation , if the bases are same in both L.H.S. & R.H.S. then , the power of the bases on both the sides of equation should be equal. For e.g. :
⇒
[∵ Bases are equal on both the sides]
<u>__________________________________________________________</u>

Lets express it in terms of 2.




Here the bases on both the sides are equal. Hence ,


