I would think its $42 but thats just my op ion <span />
Answer:
Step-by-step explanation:
1. yes
2. 0.048955
3. equal, not equal, less than and equal to, less than, greater than and equal to, greater than
4. 9 51/250
5. 387.5%
Sum/difference:
Let
![x = 5 + (-3\sqrt{8}) = 5-3\sqrt{8}](https://tex.z-dn.net/?f=%20x%20%3D%205%20%2B%20%28-3%5Csqrt%7B8%7D%29%20%3D%205-3%5Csqrt%7B8%7D%20)
This means that
![3\sqrt{8} = 5-x \iff \sqrt{8} = \dfrac{5-x}{3}](https://tex.z-dn.net/?f=%203%5Csqrt%7B8%7D%20%3D%205-x%20%5Ciff%20%5Csqrt%7B8%7D%20%3D%20%5Cdfrac%7B5-x%7D%7B3%7D%20)
Now, assume that
is rational. The sum/difference of two rational numbers is still rational (so 5-x is rational), and the division by 3 doesn't change this. So, you have that the square root of 8 equals a rational number, which is false. The mistake must have been supposing that
was rational, which proves that the sum/difference of the two given terms was irrational
Multiplication/division:
The logic is actually the same: if we multiply the two terms we get
![x = -15\sqrt{8}](https://tex.z-dn.net/?f=%20x%20%3D%20-15%5Csqrt%7B8%7D%20)
if again we assume x to be rational, we have
![\sqrt{8} = -\dfrac{x}{15}](https://tex.z-dn.net/?f=%20%5Csqrt%7B8%7D%20%3D%20-%5Cdfrac%7Bx%7D%7B15%7D%20)
But if x is rational, so is -x/15, and again we come to a contradiction: we have the square root of 8 on one side, which is irrational, and -x/15 on the other, which is rational. So, again, x must have been irrational. You can prove the same claim for the division in a totally similar fashion.
It depends on your fuel economy, how much fuel the car burns per 100 miles etc.