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NeX [460]
3 years ago
13

Two hundred percent more than 50 is? a).100 b).150 c).175 d).200 e).250

Mathematics
2 answers:
LenaWriter [7]3 years ago
6 0
150 is the answer I think :) 
ivann1987 [24]3 years ago
3 0
50+2\cdot50=50+100=150
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How many 10 kobo coins are there in #9.90?
baherus [9]

Answer:

99

Step-by-step explanation:

1₦ = 100 k

₦9.90 =?

=990k

990/10=99

4 0
2 years ago
When it is 6:00 a.m. in Honolulu, it is 3:00 p.m. in London. Just before Paul’s flight from Honolulu to London, he called his fr
sineoko [7]

Answer:

b. winter wear, appropriate for around 20-45°F

Step-by-step explanation:

When it is 6:00 hours in Honolulu, it is 15:00 hours in London, this means that there are 15 - 6 = 9 hours of difference.

Paul got into London at 12:00 p.m, that is, at 12 - 9 = 3:00 p.m. Friday Honolulu time. Paul’s flight left Honolulu at 2:00 p.m. Thursday, so he spent 25 hours flighting.

When the flight started, the temperature in London was 30 °C, after 25 hours the temperature dropped 25 °C, so it was 30 - 25 = 5 °C.

To convert from °C to °F, we use the following formula:

(x °C × 9/5) + 32 = y °F

Replacing with x = 5

(5 °C × 9/5) + 32 = 41 °F

6 0
3 years ago
Read 2 more answers
A rectangle has an area of 72 in². The length and the width of the rectangle are changed by a scale factor of 3.5. What is the a
kifflom [539]

Answer:

The area of the new rectangle is 882 in².

Step-by-step explanation:

Let l be the length and w be the width of the original rectangle,

So, the area of the original rectangle is,

A = l × w                  ( Area of a rectangle = Length × Width )

Given, A = 72 in²,

⇒ lw = 72 ------- (1),

Since, if the rectangle are changed by a scale factor of 3.5,

⇒ New length = 3.5 l,

And, new width = 3.5 w,

Thus, the area of the new rectangle = 3.5l × 3.5w

=(3.5)^2lw

=12.25\times 72  ( From equation (1) ),

= 882 in²

4 0
3 years ago
How many terms are there in the sequence 1, 8, 28, 56, ..., 1 ?
BabaBlast [244]

Answer:

9 terms

Step-by-step explanation:

Given:  

1, 8, 28, 56, ..., 1

Required

Determine the number of sequence

To determine the number of sequence, we need to understand how the sequence are generated

The sequence are generated using

\left[\begin{array}{c}n&&r\end{array}\right] = \frac{n!}{(n-r)!r!}

Where n = 8 and r = 0,1....8

When r = 0

\left[\begin{array}{c}8&&0\end{array}\right] = \frac{8!}{(8-0)!0!} = \frac{8!}{8!0!} = 1

When r = 1

\left[\begin{array}{c}8&&1\end{array}\right] = \frac{8!}{(8-1)!1!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8

When r = 2

\left[\begin{array}{c}8&&2\end{array}\right] = \frac{8!}{(8-2)!2!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} =2 8

When r = 3

\left[\begin{array}{c}8&&3\end{array}\right] = \frac{8!}{(8-3)!3!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56

When r = 4

\left[\begin{array}{c}8&&4\end{array}\right] = \frac{8!}{(8-4)!4!} = \frac{8!}{4!3!} = \frac{8 * 7 * 6 * 5 * 4!}{4! *4*3* 2 *1} = \frac{8 * 7 * 6*5}{4*3 *2 *1} = 70

When r = 5

\left[\begin{array}{c}8&&5\end{array}\right] = \frac{8!}{(8-5)!5!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56

When r = 6

\left[\begin{array}{c}8&&6\end{array}\right] = \frac{8!}{(8-6)!6!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} = 28

When r = 7

\left[\begin{array}{c}8&&7\end{array}\right] = \frac{8!}{(8-7)!7!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8

When r = 8

\left[\begin{array}{c}8&&8\end{array}\right] = \frac{8!}{(8-8)!8!} = \frac{8!}{8!0!} = 1

The full sequence is: 1,8,28,56,70,56,28,8,1

And the number of terms is 9

3 0
3 years ago
3. What three numbers are the Pythagorean triple generated by using 4 for x and 1 for y. Remember to use the formulas:
Gnom [1K]

Given:

The three equations for the three numbers are

a=x^2-y^2

b=2xy

c=x^2+y^2

To find:

The Pythagorean triple generated by using 4 for x and 1 for y.

Solution:

Substituting x=4 and and y=1 in the given equations, we get

a=4^2-1^2

a=16-1

a=15

In the same way find b and c.

b=2(4)(1)

b=8

The third number is

c=4^2+1^2

c=16+1

c=17

The required Pythagorean triple is 8, 15, and 17.

Therefore, the correct option is C.

5 0
3 years ago
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