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3 years ago

6

Mathematics

1 answer:

Drupady [299]3 years ago

5 0

Answer:

(a) 1/2
(b) 1/3

Step-by-step explanation:

(a) 3 of the 6 numbers on the die are even, so the probability that one of them will show is 3/6 = 1/2.

(b) 2 of the 6 numbers on the die are less than 3, so the probability that one of them will show is 2/6 = 1/3.

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If you take 5 quizzes and get scores of 95%, 95%, 80%, 85%, and 75%, how would you find your mean quiz score?

avanturin [10]

Answer:

The answer is C.

Step-by-step explanation:

Remember, to find the mean of some scores, you must add all the scores together, then you must divide by the number of scores you added. In this case, you would divide by four, because you had four numbers you added to gether.

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2 years ago

Find the difference in simplest form:

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D. is the answer I got i think it is right but IDK

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3 years ago

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What is the equation of the circle center (0, 3) and radius 4?

Sunny_sXe [5.5K]

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( x )² + ( y - 3 )² = 16

Step-by-step explanation:

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3 years ago

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How many randomly chosen guests should I invite to my party so that the probability of having a guest with the same birthday as

dimulka [17.4K]

Answer:

At least 401 chosen guests

Step-by-step explanation:

Represent those with same birth day with Same

So:

$P(Same) > \frac{2}{3}$

Represent number of people with n

There are 365 days in a year and 364 days out of these days is not your birthday.

So, there the probability that n people do not share your birthday is $(\frac{364}{365})^n$

i.e.

$P(none) = (\frac{364}{365})^n$

Solving further, we have that:

$P(same) + P(none) = 1$

$P(same) + (\frac{364}{365})^n = 1$

$P(same) = 1 - (\frac{364}{365})^n$

We're calculating the probability that $P(Same) > \frac{2}{3}$ .

So, we have:

$1 - (\frac{364}{365})^n > \frac{2}{3}$

Collect Like Terms

$1 - \frac{2}{3}> (\frac{364}{365})^n$

$\frac{3-2}{3}> (\frac{364}{365})^n$

$\frac{1}{3}> (\frac{364}{365})^n$

$3^{-1} > (\frac{364}{365})^n$

Take natural logarithm (ln) of both sides

$ln(3^{-1}) > ln((\frac{364}{365})^n)$

$-ln\ 3 > n\ ln\ (\frac{364}{365})$

Apply laws of logarithm

$-ln\ 3 > n\ (ln(364) - ln(365))$

Multiply through by -1

$ln\ 3 < n\ (ln(365) - ln(364))$

Solve for n

$\frac{ln\ 3}{(ln(365) - ln(364))} < n$

Reorder

$n > \frac{ln\ 3}{(ln(365) - ln(364))}$

$n > \frac{1.09861228867}{(5.89989735358 - 5.89715386764)}$

$n> \frac{1.09861228867}{0.00274348594}$

$n > 400.443928891$

$n > 400$ (approximated)

This implies that n = 401, 402, 403 .....

i.e

$n \geq 401$

So, at least 401 people has to be invited

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3 years ago

Given f z please help

Softa [21]

Answer:

z = -11, z = -2

Step-by-step explanation:

Given that, ( $f(z)=\sqrt{z+27} -z$ ) and ( $f(z)=7$ ), set up an equation that puts the first value of ( $f(z)$ ) equal to the other given value of the function.