Answer: the answer in c on edge
Step-by-step explanation:
Answer:
C. ∆ABD ≅ ∆CBD by the SSS Postulate
Step-by-step explanation:
We can prove that ∆ABD and ∆CBD congruent by the SSS Postulate.
The SSS postulate states that of three sides in one triangle are congruent to three corresponding sides in another, therefore, the two triangles are congruent.
From the diagram shown,
AB ≅ CB,
AD ≅ CD
BD = BD
We have three sides in ∆ABD that are congruent to three corresponding sides in ∆CBD.
Therefore, ∆ABD ≅ ∆CBD by the SSS Postulate
Answer:
<h2>no solution</h2>
Step-by-step explanation:
Answer:
n=-17
Step-by-step explanation:
8(2n-5)=3(6n-2)
1) Distributive property
16x-40=18x-6
16x−40=18x−6
2) Subtract 16x16x from both sides.
-40=18x-6-16x
−40=18x−6−16x
3) Simplify 18x-6-16x18x−6−16x to 2x-62x−6.
-40=2x-6
−40=2x−6
4) Add 66 to both sides.
-40+6=2x
−40+6=2x
5) Simplify -40+6−40+6 to -34−34.
-34=2x
−34=2x
6) Divide both sides by 22.
-\frac{34}{2}=x
−
2
34
=x
7) Simplify \frac{34}{2}
2
34
to 17
−17=x
8) Switch sides.
x=−17
The MAD is 2.4861 (1repeating) <span> I hope that helps :-) Good luck</span>
