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Pachacha [2.7K]
11 months ago
13

Please select either A,B,C, or D in the end.(Info in photo)

Mathematics
1 answer:
Anna [14]11 months ago
5 0

The volume of a pyramid can be calculated as:

V=\frac{1}{3}\cdot B\cdot H

Where B is the area of the base and H is the height. We are given V = 60 cubic inches and H = 5 inches. Solving for B:

B=\frac{3V}{H}

Substituting:

B=\frac{3\cdot60in^3}{5in}=36in^2

The area of the base is 36 square inches.

We must choose the option whose area is 36 sq in.

A square of a side length of 6 inches has an area of:

A=(6in)^2=36in^2

Thus, the correct choice is D.

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Consider the line =−−8x6y1.
ICE Princess25 [194]

Answer:

Below

Step-by-step explanation:

Well I can't really see the equation but I can tell you how to do it.

Parallel slopes are the same slope as the equation.

For example, y = mx + b

The slope of a line parallel to it is m

Perpendicular slopes are the opposite reciprocal as the equation.

For example, y = mx + b

The slope of a line perpendicular to it is-\frac{1}{m}

6 0
3 years ago
2. Draw the image of RST under the dilation with scale factor 2/3 and center of dilation (1,-1). Label the image RST .
professor190 [17]

Answer:

From the graph: we have the coordinates of RST i.e,

R = (2,1) , S = (2,-2) , T = (-1,-2)

Also, it is given the scale factor \frac{2}{3} and center of dilation C (1,-1)

The mapping rule for the center of dilation applied for the triangle as shown below:

(x, y) \rightarrow (\frac{2}{3}(x-1)+1, \frac{2}{3}(y+1)-1)

or

(x, y) \rightarrow (\frac{2}{3}x -\frac{2}{3}+1 , \frac{2}{3}y+\frac{2}{3}-1)

or

(x, y) \rightarrow (\frac{2}{3}x+\frac{1}{3} , \frac{2}{3}y-\frac{1}{3} )

Now,  

for R = (2,1)  

the image R' = (\frac{2}{3}(2)+\frac{1}{3} , \frac{2}{3}(1)-\frac{1}{3} ) or

(\frac{4}{3}+\frac{1}{3} , \frac{2}{3}-\frac{1}{3} )

⇒ R' = (\frac{5}{3} , \frac{1}{3})  

For S = (2, -2) ,

the image S'=  (\frac{2}{3}(2)+\frac{1}{3} , \frac{2}{3}(-2)-\frac{1}{3} ) or

(\frac{4}{3}+\frac{1}{3} , \frac{-4}{3}-\frac{1}{3} )

⇒ S' = (\frac{5}{3} , -\frac{5}{3})

and For T = (-1, -2)

The image T' =  (\frac{2}{3}(-1)+\frac{1}{3} , \frac{2}{3}(-2)-\frac{1}{3} ) or

(\frac{-2}{3}+\frac{1}{3} , \frac{-4}{3}-\frac{1}{3} )

⇒ T' = (\frac{-1}{3} , \frac{-5}{3})

Now, label the image of RST on the graph as shown below in the attachment:

5 0
2 years ago
Solve quadratic equation x²-8x-1=0 by formula method​
Alex_Xolod [135]

Answer:

x²-8x-1=0

comparing above equation with ax²+bx+c=0

a=1

b=-8

c=-1

x=

x =  \frac{ - b +  -  \sqrt{ {b}^{2} - 4ac } }{2a}

=(--8+-√(64-4×1×-1)/2×1

=8+-√(64+4)/2

taking positive

x=(8+√68)/2=2(4+√17)/2=4+√17

taking negative

x=(8-√68)/2=2(4-√17)/2=4-√17

6 0
2 years ago
Read 2 more answers
Find the great is perfect square of 244
IgorLugansk [536]
I hope this helps you



244=4.61


2square roof 61
7 0
3 years ago
If the speed of a is 3 ft/s up and is increasing at 4 what is the instantaneous speed and acceleration
Tasya [4]
Sorry I'm in high school.. but according to my physics class, the instantaneous speed is when t (time) is 0, or whatever you'd use (like x).. anyways, when t=0, the instantaneous speed would be 3 ft/s, and the instantaneous acceleration is 0.
6 0
3 years ago
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