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pishuonlain [190]
3 years ago
8

Draw the products of the transformation shown by the fishhook notation. Include any electrons.

Chemistry
1 answer:
andrew11 [14]3 years ago
4 0

Answer:

Explanation:

The question is based on the concept of the cleavage of bonds. In the process of the reaction the breaking of bonds is required. The cleavage of the bonds make the bonded electrons free to involve in the reaction process.

Fundamentals:

The cleavage of the bond can be done in two ways: homolytic or heterolytic. The heterolytic cleavage occurs when the shared electrons of the covalent bond are taken away by either of the atom. The heterolytic cleavage results in generation of the charged molecules. On the other hand, the homolytic cleavage is the cleavage in which the shared pair of the electrons are equally distributed, resulting in generation of free radicals.

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A rectangular tank is filled with water to a depth = h, the tank width and length are w and 1 respectively. Calculate the ratio
AnnZ [28]

Answer:

\frac{\textup{2}}{h}

Explanation:

Given:

Depth = h

Width = w

Length  = 1

Now,

Let ρ be the density of water

Thus,

Pressure force at the bottom will be

= Pressure × Area

= ρgh × (w × 1)

also,

Pressure force at the sides will be = \frac{\textup{1}}{\textup{2}}\times ρgh × (h × w)

Therefore,

The ratio of the pressure force at the bottom to the pressure force on the side of the tank will be

= \frac{\rho gh\times w\times1}{\frac{1}{2}\times\rho gh\times(h\timesw)}

= \frac{\textup{2}}{h}

8 0
3 years ago
What would be the composition and ph of an ideal buffer prepared from lactic acid (ch3chohco2h), where the hydrogen atom highlig
Mashutka [201]

Answer:

P_H =2.86

c=1.4\times 10^{-4}

Explanation:

first write the equilibrium equaion ,

C_3H_6O_3  ⇄ C_3H_5O_3^{-}  +H^{+}

assuming degree of dissociation \alpha =1/10;

and initial concentraion of C_3H_6O_3 =c;

At equlibrium ;

concentration of C_3H_6O_3 = c-c\alpha

[C_3H_5O_3^{-}  ]= c\alpha

[H^{+}] = c\alpha

K_a = \frac{c\alpha \times c\alpha}{c-c\alpha}

\alpha is very small so 1-\alpha can be neglected

and equation is;

K_a = {c\alpha \times \alpha}

[H^{+}] = c\alpha = \frac{K_a}{\alpha}

P_H =- log[H^{+} ]

P_H =-logK_a + log\alpha

K_a =1.38\times10^{-4}

\alpha = \frac{1}{10}

P_H= 3.86-1

P_H =2.86

composiion ;

c=\frac{1}{\alpha} \times [H^{+}]

[H^{+}] =antilog(-P_H)

[H^{+} ] =0.0014

c=0.0014\times \frac{1}{10}

c=1.4\times 10^{-4}

6 0
4 years ago
An object has a mass of 180 kg and a volume of 90 m3. what is its density?
Murljashka [212]
Divide 180kg and 90m3 and your density will be 2kg/m3
8 0
3 years ago
Read 2 more answers
The volume of a solid is the amount of space inside the solid? true or false
grin007 [14]
The answer is true.....
8 0
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In carbon dioxide (CO2), there are two oxygen atoms for each carbon atom. Each oxygen atom forms a double bond with carbon, so t
SashulF [63]

Answer:

The Answer is eight.

Explanation:

Sorry if it's too late and it doesn't help! But I hope you have a magnificent day! :3

4 0
3 years ago
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