Answer:
2 AsCl₃ + 3 H₂S → As₂S₃ + 6 HCl
Explanation:
When we balance a chemical equation, what we are trying to do is to achieve the same number of atoms for each element on both sides of the arrow. On the right of the arrow is where we can find the products, while the reactants are found on the left of the arrow.
We usually balance O and H atoms last.
AsCl₃ + H₂S → As₂S₃ +HCl
<u>reactants</u>
As --- 1
Cl --- 3
H --- 2
S --- 1
<u>products</u>
As --- 2
Cl --- 1
H --- 1
S --- 3
2 AsCl₃ + H₂S → As₂S₃ +HCl
<u>reactants</u>
As --- 2
Cl --- 6
H --- 2
S --- 1
<u>products</u>
As --- 2
Cl --- 1
H --- 1
S --- 3
The number of As atoms is now balanced.
2 AsCl₃ + 3 H₂S → As₂S₃ +HCl
<u>reactants</u>
As --- 2
Cl --- 6
H --- 6
S --- 3
<u>products</u>
As --- 2
Cl --- 1
H --- 1
S --- 3
The number of S atoms is now equal on both sides.
2 AsCl₃ + 3 H₂S → As₂S₃ + 6 HCl
<u>reactants</u>
As --- 2
Cl --- 6
H --- 6
S --- 3
<u>products</u>
As --- 2
Cl --- 6
H --- 6
S --- 3
The equation is now balanced.
Answer:
Solutions are always homogeneous.
Explanation:
Solution:
Solution are considered homogeneous because in solution the ratio of solute and solvent remain the same throughout the solution. Both solute and solvent are chemically combined and form a new substance.
In solution the particles of solute can not be seen through naked eye.
When the light is passed through the solution it can not scattered.
Example:
When salt is dissolve in water it makes a solution.
The solution also exist in gaseous form. For example oxygen and many other gases dissolved in nitrogen also form a solution.
Mixture:
In mixture substance are physically combined. In mixture every every individual particle retain their properties.
It can be consist of solid, liquid and gas.
Examples:
Sand in water is also a mixture.
Oil in water form mixture.
Answer:
The answer is c radio --> infrared --> ultraviolet --> gamma
Explanation:
I just did it
C. Weak acids partially ionize
<span>Ans :
The chemical formula for aluminum sulfate is Alâ‚‚(SOâ‚„)â‚
6.00 mol Alâ‚‚(SOâ‚„)â‚
Al: 6.00 mol Alâ‚‚(SOâ‚„)â‚ x (2 mol Al / 1 mol Alâ‚‚(SOâ‚„)â‚ ) = 12.00 mol Al
S: 6.00 mol Alâ‚‚(SOâ‚„)â‚ x (3 mol S / 1 mol Alâ‚‚(SOâ‚„)â‚ ) = 18.00 mol S
O: 6.00 mol Alâ‚‚(SOâ‚„)â‚ x (12 mol O / 1 mol Alâ‚‚(SOâ‚„)â‚ ) = 72.00 mol O</span>
