Answer:
I attached the answer as an image. I also drew in the two most acidic hydrogens.
Explanation:
This goes through the 'benzyne' intermediate, meaning it does an E2-looking reaction by expelling a leaving group (chloride) from the adjacent part of the ring using the amide as a strong base. The triple-bonded benzyne has absurd bond angle strain, and is vulnerable to a good nucleophile like an amide ion, and the resultant sp2 anion is then reprotonated by the acid. I didn't draw in the acid-base reaction in step one, or the spectator ion (sodium).
The specific heat of metal is c = 3.433 J/g*⁰C.
<h3>Further explanation</h3>
Given
mass of metal = 68.6 g
t metal = 100 °C
mass water = 84 g
t water = 20 °C
final temperature = 52.1 °C
Required
The specific heat
Solution
Heat can be formulated :
Q = m.c.Δt
Q absorbed by water = Q released by metal
84 x 4.184 x (52.1-20)=68.6 x c x (100-52.1)
11281.738=3285.94 x c
c = 3.433 J/g*⁰C.
Answer: (2)3.0 mol
Explanation: 222.3g= 222.3/74= 3.0 mol
1mol Ca(OH)2 is 74g
Noble Gas. Metals have 1 or 2 Valence Electrons. Halogens have 7 Valence Electrons. Semi-Metals can have different amounts.