Question

Using the balanced equation below, how many grams of iron(iii) oxide would be required to make 187g iron Fe2O3+3CO = 2Fe+3CO2

Answer 1

Answer:

267.14 iron oxide.

Explanation:

Given that

$Fe_2O_3+3CO = 2Fe+3CO_2$

We know that molecular mass of iron-oxide = 160 g/mole.

We know that molecular mass of iron = 56 g/mole.

From the above reaction we can say that

1 mole of iron -oxide produce 2 mole of iron

160 gm of iron oxide produce 112 gm of iron

So

1 gm of iron required $\dfrac{160}{112}=1.42 gm$ of iron oxide

Therefore

187 gm of iron required $1.42\times = 187 = 267.14\ gm$ of iron oxide.

Therefore 187 gm of iron required 267.14 iron oxide.