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KIM [24]
3 years ago
11

Describe in words the region of R3 reperesented by the equations or inequalities x2+y2+z2≤3

Mathematics
1 answer:
Vaselesa [24]3 years ago
8 0

Answer:

The region represented by the equation is a full sphere of radius √3 centered in the origin of coordinates.

Step-by-step explanation:

<em>In a plane xy, the equation that represents a circle with center in the origin, of radius r is</em>

x^2+y^2=r^2

<em>in R³, or a space xyz, we can represent a sphere with its center in the origin, and of radius r, with the equation</em>

x^2+y^2+z^2=r^2

So, in this problem we have that

3=r^2

which means that the sphere has a radius of √3.

<u>Finally, our equation is an inequality</u>, and the sphere is equal to, and less than, the calculated radius.

Therefore, the sphere is "full" from the surface to its center.

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A suitcase measures 24 inches long and the dialogue is 30 inches long. How much material is needed to cover one side of the suit
borishaifa [10]

Answer:

432 in.^2

Step-by-step explanation:

The side of the suitcase is a rectangle. One length is 24 inches. The diagonal of the rectangle is 30 inches long. The diagonal is a hypotenuse of a right triangle. The length is a leg. We need to find the other leg.

We use the Pythagorean theorem,

a^2 + b^2 = c^2

(24 in.)^2 + b^2 = (30 in.)^2

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b = sqrt(324 in^2)

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area of rectangle = length * width

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A = 432 in.^2

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3 years ago
Hector is dividing students into groups for an HR wants to divide the boys and girls so that each group has the same number of t
Roman55 [17]

Answer:

7 groups, 3 boys and 8 girls

Step-by-step explanation:

Let total number of groups be x

and total hikers in one group be y

if number of girls and boys in every group is same, then

\frac{21}{x} + \frac{56}{x} = y

\frac{21 + 56}{x} = y\\x*y = 77 ....(1)

from (1) x will either be 11 or 7

for x = 11 the values won't be real.

For x = 7\\y = \frac{77}{7} \\y = 11

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6 0
3 years ago
Solve 3x^2 + 6x+15=0
Elden [556K]

Answer:

The solution of given equation is ( - 1 + 2 i ) , ( - 1 - 2 i )

Step-by-step explanation:

Given equation as :

3 x² + 6 x +15 = 0

The value of x fro the quadratic equation a x² + b x + c = 0 is obtained as

x = \frac{-b\pm \sqrt{b^{2}-4ac}}{2a}

So , from given eq , the value of x is now obtain as

x = \frac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}

Or, x =  \frac{-6\pm \sqrt{6^{2}-4\times 3\times 15}}{2\times 3}

Or, x = \frac{\sqrt{-144} }{6}

∴   x = ( - 1 + 2 i ) , ( - 1 - 2 i )

Hence The solution of given equation is ( - 1 + 2 i ) , ( - 1 - 2 i )  Answer

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