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mash [69]
3 years ago
14

I’m confused on this one

Mathematics
2 answers:
IceJOKER [234]3 years ago
7 0
The answer should be graph b
Sati [7]3 years ago
3 0

B shows symmetry in the origin

Answer is B.

Hope it helps

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There are no solutions to the system of inequalities shown belov
Aleks04 [339]

Answer:

B. False

step by step explanation

3 0
2 years ago
A Ferries wheel had a radius of 58 feet. What is the distance a passenger will travel one time around the Ferries wheel?
topjm [15]

Answer:

364.42 ft.

Step-by-step explanation:

For step 1 we should multiply pi by r and 2.

π x r x 2

For step 2 we should multiply pi by 58 and 2.

π x 58 x 2

In result, we should end up with 364.424748 ft. or for short 364.42 ft.

I hope I helped you... Have a great and nice day! :D

5 0
3 years ago
Subtract the following polynomials, then place the answer in the proper location on the grid.
melamori03 [73]
When we add or subtract polynomials, the addition or subtraction is applied to the coefficients of the terms of equal powers.

For the given polynomials, we are required to do subtraction as follows:
(-4.1 x^2 + 0.9 x - 9.8) - (1.7 x^2 - 2.4 x - 1.6)
= -4.1 x^2 + 0.9 x - 9.8 - 1.7 x^2 + 2.4 x + 1.6
= (-4.1-1.7) x^2 + (0.9+2.4) x + (-9.8+1.6)
= -5.8 x^2 + 3.3 x - 8.2

The final expression (solution) is:
-5.8 x^2 + 3.3 x - 8.2

8 0
3 years ago
A student was given the line y=2/3x-1 and the point (-7, 1/2) and asked to find an equation that went through the given point an
Colt1911 [192]

keeping in mind that perpendicular lines have <u>negative reciprocal</u> slopes,  hmmm what's the slope of y=2/3x-1 anyway?


\bf \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}~\hspace{7em}y=\stackrel{\stackrel{m}{\downarrow }}{\cfrac{2}{3}}x-1 \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{2}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{3}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{3}{2}}}


so, notice, "one of his mistakes" is that he used 3/2 as the slope, not -3/2.

so, we're really looking for a line whose slope is -3/2 and runs through (-7, 1/2).


\bf (\stackrel{x_1}{-7}~,~\stackrel{y_1}{\frac{1}{2}})~\hspace{10em} slope = m\implies -\cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\cfrac{1}{2}=-\cfrac{3}{2}[x-(-7)]\implies y-\cfrac{1}{2}=-\cfrac{3}{2}(x+7) \\\\\\ y-\cfrac{1}{2}=-\cfrac{3}{2}x-\cfrac{21}{2}\implies y=-\cfrac{3}{2}x-\cfrac{21}{2}+\cfrac{1}{2}\implies y=-\cfrac{3}{2}x-10

3 0
3 years ago
In ΔFKR, which side is included between ∠F and ∠R?
alisha [4.7K]

Answer:

c

Step-by-step explanation:

the K is the one that is in the center so that would be the answer

5 0
2 years ago
Read 2 more answers
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