Answer:
% Remaining![= [1-(1/2)^{\frac{t}{2.6}}]x100](https://tex.z-dn.net/?f=%20%3D%20%5B1-%281%2F2%29%5E%7B%5Cfrac%7Bt%7D%7B2.6%7D%7D%5Dx100%20)
And replacing the value t =5.5 hours we got:
% Remaining![= [1-(1/2)^{\frac{5.5}{2.6}}]x100 =76.922\%](https://tex.z-dn.net/?f=%20%3D%20%5B1-%281%2F2%29%5E%7B%5Cfrac%7B5.5%7D%7B2.6%7D%7D%5Dx100%20%3D76.922%5C%25)
Step-by-step explanation:
Previous concepts
The half-life is defined "as the amount of time it takes a given quantity to decrease to half of its initial value. The term is most commonly used in relation to atoms undergoing radioactive decay, but can be used to describe other types of decay, whether exponential or not".
Solution to the problem
The half life model is given by the following expression:
Where A(t) represent the amount after t hours.
represent the initial amount
t the number of hours
h=2.6 hours the half life
And we want to estimate the % after 5.5 hours. On this case we can begin finding the amount after 5.5 hours like this:
Now in order to find the percentage relative to the initial amount w can use the definition of relative change like this:
% Remaining = 
We can take common factor and we got:
% Remaining
And replacing the value t =5.5 hours we got:
% Remaining ![= [1-(1/2)^{\frac{5.5}{2.6}}]x100 =76.922\%](https://tex.z-dn.net/?f=%3D%20%5B1-%281%2F2%29%5E%7B%5Cfrac%7B5.5%7D%7B2.6%7D%7D%5Dx100%20%3D76.922%5C%25)
Answer:
The scale factor is 1.5
Step-by-step explanation:
Given
Required
Determine the scale factor
The scale factor (k) is calculated using:
Substitute values for OA and OA'
<em>The scale factor is 1.5</em>
A) From the function p(t)=6(t), we know that p is 6t, so we plug this into it, to get 3.14 * (6t)^2, or 113.04t^2.
B) Using what we got from A), we plug it in and get 113.04 * 8 * 8, or 7234.56 (Use a calculator on this, or just bash it with pencil and paper).
9/10 equals 0.9 , 2/7 equals about 0.28 . So 0.9 - 0.28 = 0.62 if you need .62 in a fraction it's 31/50
Answer:
Step-by-step explanation:
Side A is the longest side
Side B is half of A = A/2
Side C is 8m less than A = A-8
Perimeter of traingle = A+B+C
52 = A + A/2 + A-8
Collect like terms
52+8= A+A/2+A
60 = 5/2 A
Divide 60 by the coefficient of A
60÷5/2 = A
60×2/5= A
A=24m
Substitute the value of A into the expressions for sides B and C
Side B =A/2=24/2=12m
Side C =A-8=24-8=16m
The sides of the triangle are 24m, 12m and 16m
