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olga55 [171]
3 years ago
6

Numbers that are divisible by 2,4,6,8 and 10 have to be ___.

Mathematics
2 answers:
Lesechka [4]3 years ago
3 0

Answer:

They have to be even.

Step-by-step explanation:

Because all these numbers are multiples of 2, and 2 is even, all of these must also be even.

Hoochie [10]3 years ago
3 0
They have to be even
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Answer:

A, (Hope that was correct)

Step-by-step explanation:

4 0
3 years ago
E^2x -2e^x -8=0<br><img src="https://tex.z-dn.net/?f=%20%7Be%7D%5E%7B2x%7D%20-%20%20%7B2e%7D%5E%7Bx%7D%20-%208%20%3D%200" id="Te
vovikov84 [41]
E^2x -2e^x -8=0   =>    e<span>^(2x)  -2e^x -8=0

Temporarily replace e^x with y.

Then (y)^2 - 2y - 8 = 0.  Factors are (y-4) and (y+2).

Roots are y = 4 and y= -2.

Now remembering that we temporarily replaced e^x with y, we let 
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ln 4 = x (answer)

We have to discard the other root (y= -2), because we cannot take the ln of a negative number.


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3 years ago
A rectangle's length is 6 units greater than its width. write an equation expressing the rectangle's area, a, as a function of w
vladimir1956 [14]
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shepuryov [24]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
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2. Find the product of each of the following:
Kruka [31]

Step-by-step explanation:

i) \:  \frac{3}{5}  \times (   \frac{ - 7}{8} ) =  -  \frac{21}{40}  \\  \\ ii) \:  \frac{ - 9}{2}  \times  \frac{5}{4}  =   - \frac{45}{8}  \\  \\ iii) \:  \frac{ - 6}{11}  \times  \frac{5}{3}  =  -  \frac{10}{11}  \\  \\ iv) \:  \frac{ - 2}{3}   \times  \frac{6}{7}  =  -  \frac{4}{7}  \\

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3 years ago
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