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rjkz [21]
3 years ago
14

10 points need help asap image to help

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
3 0
Its A because 25 is taken out of m=bday money m-$25
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I need help with this question pls
Mumz [18]

Answer:

C

Step-by-step explanation:

SA=pi*r^2+pi*r*s

SA=3.14*3^2+3.14*3*8

SA=3.14*9+3.14*24

SA=103.62

SA= about 104 inches

Aubrey included the base (you can't put on a hat that has a bottom), the right work should be:

SAhat=pi*r*s

SAhat=3.14*3*8

SAhat=3.14*24

SAhat=75.36

SAhat= about 75

Thus, answer is C

7 0
3 years ago
Is 11/28 a terminating decimal or a repeating decimal ? Explain how you know
Natasha2012 [34]

We need to determine whether  is a terminating decimal or a repeating decimal.

Let's solve this question using the long division method

First, let's identify the divisor and dividend. The number to be divided is 11 hence this is the dividend, and it needs to be divided by 128 which is the divisor

Next, since the divisor (128) is greater than the dividend (11) it can not divide 11. Hence, we will introduce a decimal point in quotient, and append a 0 next to 11 and divide 110 by 128. Again, 128 is greater than 110 so we will introduce a 0 in the quotient, and append another 0 next to 110, and will divide 1100 by 128. We will see what multiple of 128 is less than or equal to 1100. That multiple is 8. So we write 8 in the quotient and multiply 128 with 8 and subtract the product (128*8 = 1024) from 1100. The remainder that we get is 76.

Next, we append a 0 to the remainder and divide 760 by 128. Now, we see what multiple of 128 is less than or equal to 760. That multiple is 5. So we write 5 next to the quotient and multiply 128 with 5 and subtract the product (640) from 760. Now, the remainder is 120.

Next, we append a 0 to the remainder and divide 1200 by 128. Now, we see what multiple of 128 is less than or equal to 1200. That multiple is 9. So we write 9 next to the quotient and multiply 128 with 9 and subtract the product (1152) from 1200. Now, the remainder is 48.

Next, we append a 0 to the remainder and divide 480 by 128. Now, we see what multiple of 128 is less than or equal to 480. That multiple is 3. So we write 3 next to the quotient and multiply 128 with 3 and subtract the product (384) from 480. Now, the remainder is 96.

Next, we append a 0 to the remainder and divide 960 by 128. Now, we see what multiple of 128 is less than or equal to 960. That multiple is 7. So we write 7 next to the quotient and multiply 128 with 7 and subtract the product (896) from 960. Now, the remainder is 64.

Next, we append a 0 to the remainder and divide 640 by 128. Now, we see what multiple of 128 is less than or equal to 640. That multiple is 5. So we write 5 next to the quotient and multiply 128 with 5 and subtract the product (640) from 640. Now, the remainder is 0.

Hence, we have solved the entire problem

Last, we look at the quotient i.e. 0.0859375, which is the solution to the problem. We see that the quotient has a definite number of digits in it, and terminates at 5. Hence, this is a terminating decimal.

A repeating decimal is one in which a particular pattern after the decimal point keeps re-occuring, which is not the case here. Hence,  is a terminating decimal.

Please refer to the attached image for visualization

6 0
3 years ago
Answer Answer Answer Answer Answer Answer Answer Answer Answer Answer Answer Answer Answer Answer Answer Answer Answer Answer An
garri49 [273]

Answer:

<h2>40</h2>

Step-by-step explanation:

You must multiply all prime factors:

2 · 2 · 2 · 5 = 40

6 0
3 years ago
Read 2 more answers
Consider the estimated equation from Example 4.3, which can be used to study the effects of skipping class on college GPA: 2 col
AlekseyPX

Answer:

Step-by-step explanation:

1) The confidence interval is calculated as the following

CI = ( \bar x-1.96 \sigma ,\bar x=1.96 \sigmam)

= (0.412-1.96 \times 0.094, 0.412 = 1.96 \times 0.094)\\\\= (0.22776, 0.59624)

Hence, the confidence interval is 0.22776 \leq  \beta_G_P_A \leq 0.59624)

11) Under two sid t-tailed test, the null hypothesis

H_0; \beta_{GPA}=0.4

Against the alternative hypothesis

H_1 ; \beta _{GPA} \neq 0.4

Under null hypothesis

t = \frac{\hat \beta _1 - \beta _1}{Se( \beta _1)} \\\\ =\frac{0.412-0.4}{0.094} \\\\=0.12766

The degree of freedom is n - 1 = 140

From the t - table at 5% level of significance under two - tail is 1.96

Since , calculated value is lowe than the tabulated value, we do not reject the null hypothesis.

3 0
3 years ago
Find functions f and g so that f of g = H.
den301095 [7]

Answer:

Step-by-step explanation:

Yeet

5 0
3 years ago
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