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3241004551 [841]
3 years ago
8

PLEASEEE HELP MEEEEEEEEE !!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
alukav5142 [94]3 years ago
4 0

Answer:

I'm pretty sure that it's the 3rd one

Step-by-step explanation:

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3 years ago
If x=4 and y=3 what is the value of 5x+2y-6<br><br> show how you got the answer.
Oksana_A [137]

Answer:

<em>Given </em><em>x </em><em>=</em><em> </em><em>4</em><em> </em><em>and </em><em>y </em><em>=</em><em> </em><em>3</em>

Step-by-step explanation:

5x +2y -6 = <em>5</em><em>*</em><em>4</em><em> </em><em>+</em><em> </em><em>2</em><em>*</em><em>3</em><em> </em><em>-</em><em>6</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>2</em><em>0</em><em> </em><em>+</em><em> </em><em>6</em><em> </em><em>-</em><em> </em><em>6</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>2</em><em>0</em>

7 0
3 years ago
Read 2 more answers
(x-1)^2+(2-x)^2-3(x-5)*(x-5)
Natali5045456 [20]

Answer:

-x^2+24x-70

Step-by-step explanation:

(x-1)^2+(2-x)^2-3(x-5)*(x-5)\\=> (x - 1)^2 + (2 - x)^2 - 3(x - 5)^2\\=> x^2 - 2x + 1 + 4 - 4x + x^2 - 3(x - 5)^2\\=> x^2 - 2x + 5 - 4x + x^2 - 3(x - 5)^2\\=> x^2 - 6x + 5 + x^2 - 3(x - 5)^2\\=> 2x^2 - 6x+5 - 3(x - 5)^2\\=> 2x^2 - 6x+5 - 3(x^2 - 10x + 25)\\=> 2x^2 - 6x+5  - 3x^2+30x-75\\=> -x^2 - 6x + 5 + 30x - 75\\=> -x^2 + 24x + 5-75\\=> -x^2+24x-70

Formula used =

(a-b)^2 = a^2+ 2ab + b^2

8 0
2 years ago
Please help me quick ASAP!!
Crank
A hope this helps 
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7 0
3 years ago
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The work of a student to solve a set of equations is shown below: Equation 1: x + 2y = 10 Equation 2: 2x + 5y = 15 Step 1: −2(x
DIA [1.3K]
 −2x − 4y = −10 2x + 5y = 15 
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3 years ago
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