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3 years ago

Help no guessing please explain how to solve

2 answers:

5 0

Ok so easy

I=PRT
t=time=7
r=rate3.9%=0.039
p=principal=8250

I=8250 times 0.039 times 7
I=8250 times 0.273
I=2252.25

$2252.25

ExtremeBDS [4]3 years ago

4 0

We meet again. I see you are asking about another similar equation, and I will give you the same response I did last time. You simply plug the values into the equation in solve, so it would look like this:
I=8,250*.039*7.
And you can do the rest. I hope this was helpful, have a nice day! :)

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In the right triangle shown in the diagram below,

adelina 88 [10]

QUESTION :-

what is the value of x to the nearest whole number?

ANSWER :-

$\cos( \theta) = \frac{base}{hypotenuse} \\ \cos(30) = \frac{x}{24} \\ \frac{ \sqrt{3} }{ \cancel2} = \frac{x}{ \cancel{24}} = \frac{x}{12} \\ 1.732 = \frac{x}{12} \\ 12 \times 1.732 = x \\ x = 20.7$

the nearest whole number-->

20.7 --> approximately --> 21 units

5 0

2 years ago

What is the distributive property to expand the algebraic expression.5(2f - 6g)

Gnoma [55]

Answer:

10f-30g

Step-by-step explanation:

we have:

5(2f - 6g)

we apply distributive property:

5(2f - 6g)

5*2f+5*(-6g)

finally we have:

10f-30g

7 0

3 years ago

A car is driving at a speed of 40 mi/h. What is the speed of the car in feet per minute? a. 2,400 ft/min b. 211,200 ft/min c. 3,

SCORPION-xisa [38]

Answer:

3520 ft/min

Step-by-step explanation:

40 mi/h = (40 mi/h)×(5280 ft/mi)×(1 h)/(60 min) = 3520 ft/min

_____

Each conversion factor has a value of 1 (numerator = denominator), so changes the units without changing the speed.

3 0

2 years ago

PLEASE HELP ASAP! I don’t recall how to do this!

MakcuM [25]

Answer:

Step-by-step explanation:

For a. we start by dividing both sides by 200:

$(1.05)^x=1.885$

In order to solve for x, we have to get it out from its position of an exponent. Do that by taking the natural log of both sides:

$ln(1.05)^x=ln(1.885)$

Applying the power rule for logs lets us now bring down the x in front of the ln:

x * ln(1.05) = ln(1.885)

Now we can divide both sides by ln(1.05) to solve for x:

$x=\frac{ln(1.885)}{ln(1.05)}$

Do this on your calculator to find that

x = 12.99294297

For b. we will first apply the rule for "undoing" the addition of logs by multipllying:

$ln(x*x^2)=5$

Simplifying gives you

$ln(x^3)=5$

Applying the power rule allows us to bring down the 3 in front of the ln:

3 * ln(x) = 5

Now we can divide both sides by 3 to get

$ln(x)=\frac{5}{3}$

Take the inverse ln by raising each side to e:

$e^{ln(x)}=e^{\frac{5}{3}}$

The "e" and the ln on the left undo each other, leaving you with just x; and raising e to the power or 5/3 gives you that

x = 5.29449005

For c. begin by dividing both sides by 20 to get:

$\frac{1}{2}=e^{.1x}$

"Undo" that e by taking the ln of both sides:

$ln(.5)=ln(e^{.1x})$

When the ln and the e undo each other on the right you're left with just .1x; on the left we have, from our calculators:

-.6931471806 = .1x

x = -6.931471806

Question d. is a bit more complicated than the others. Begin by turning the base of 4 into a base of 2 so they are "like" in a sense:

$(2^2)^x-6(2)^x=-8$

Now we will bring over the -8 by adding:

$(2^2)^x-6(2)^x+8=0$

We can turn this into a quadratic of sorts and factor it, but we have to use a u substitution. Let's let $u=2^x$

When we do that, we can rewrite the polynomial as

$u^2-6u+8=0$

This factors very nicely into u = 4 and u = 2

But don't forget the substitution that we made earlier to make this easy to factor. Now we have to put it back in:

$2^x=4,2^x=2$

For the first solution, we will change the base of 4 into a 2 again like we did in the beginning:

$2^2=2^x$

Now that the bases are the same, we can say that

x = 2

For the second solution, we will raise the 2 on the right to a power of 1 to get:

$2^x=2^1$

Now that the bases are the same, we can say that

x = 1

5 0

3 years ago

The missing exponent for 1/169?

enot [183]

The missing exponent of 1/169=(1/13)

5 0

3 years ago