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3 years ago

Please help!!! ive been stuck on this for 30 minutes now!

Mathematics

1 answer:

max2010maxim [7]3 years ago

7 0

Answer:

f^-1 = 4(x-3)

Step-by-step explanation:

If f(x) = 1/4(x) + 3 we ned to find f^-1.

To find the inverse function, we need to solve the equation for "x", as follows:

f(x) = 1/4(x) + 3

y = 1/4(x) + 3

y-3 = 1/4(x)

4(y-3) = x

Now, change the "x" for an "y". And change the "y" for an "x":

4(x-3) = y

The solution is the last one.

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Find a number lower than 19 that has more factors than 19,21,23, and 25

Len [333]

12 has more factors the 19,21,,23, and 25.

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3 years ago

The answer for this problem

saveliy_v [14]

Answer:

$\textbf{C}\quad\dfrac{13}{20}=\dfrac{25}{40} \qquad\textbf{FALSE}$

Step-by-step explanation:

Each of the equations represents equivalent fractions except the one in choice C.

13/20 = 26/40, not 25/40.

_____

<em>Comment on equal sign</em>

IMO, one should never use an equal sign where things are not equal--unless there is a clear indication you understand they are not equal. The equal sign should be regarded as a sacred symbol, with very specific rules as to its meaning and use.

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3 years ago

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G^2+2=0,
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3 years ago

Anwen walks at an average

Roman55 [17]

Answer:

7 km

Step-by-step explanation:

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3 years ago

Read 2 more answers

Find the perimeter of pentagon STUVW WITH VERTICES S(0,0) T(3,-2) U(2,-5) V(-2,-5) W(-3,-2)

andrew11 [14]

Use the distance formula.

$\sqrt{( x_{2} - x_{1} )^2 + (y_{2} - y_{1})^2}$

Points S and W.
$\sqrt{(3)^2 + (2)^2}$

$\sqrt{9+4}$

$\sqrt{13}$

~3.6

Points S and T
$\sqrt{(3 - 0)^2 + (-2 - 0)^2}$

$\sqrt{(3)^2 + (-2)^2}$

$\sqrt{9+4}$

$\sqrt{13}$

~3.6

Points T and U
$\sqrt{(3 - 2)^2 + (-2 + 5)^2}$

$\sqrt{(1)^2 + (3)^2}$

$\sqrt{1+9}$

$\sqrt{10}$

~3.1

Points U and V
$\sqrt{(2+2)^2 + (-5 + 5)^2}$

$\sqrt{(4)^2 + (0)^2}$

$\sqrt{16}$

~4

Points V and W
$\sqrt{(-2+3)^2 + (-5 + 2)^2}$

$\sqrt{(1)^2 + (-3)^2}$

$\sqrt{2+9}$

$\sqrt{11}$

~3.3

Add all these together.

3.3 + 3.1 + 4 + 3.1 + 3.6
≈17

4 0

3 years ago