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2 years ago

Please help!!! ive been stuck on this for 30 minutes now!

Mathematics

1 answer:

max2010maxim [7]2 years ago

7 0

Answer:

f^-1 = 4(x-3)

Step-by-step explanation:

If f(x) = 1/4(x) + 3 we ned to find f^-1.

To find the inverse function, we need to solve the equation for "x", as follows:

f(x) = 1/4(x) + 3

y = 1/4(x) + 3

y-3 = 1/4(x)

4(y-3) = x

Now, change the "x" for an "y". And change the "y" for an "x":

4(x-3) = y

The solution is the last one.

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levacccp [35]

Answer:

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8 0

2 years ago

5.b 4 of 16+8) <br>answer plz

inysia [295]

Answer:

4×16+8

=64+8

=72

hope it helps u

4 0

2 years ago

HELP PLEASE 18 POINTS

ICE Princess25 [194]

Answer:

Step-by-step explanation:

line 1 m=y2-y1 / x2-x1 [formula for slope ]

m= 0 - (-3) / 8-(-4)

m= 3 /12

m= 1/4 slope of line 1

line2

m = 2-6 / 0-(-1)

m = -4 / 1

m = -4 slope of line 2

line 3

m = -4 - (-7) / -3 - 6

m = 3 / -9

m = - 1/3 slope of line 3

lines 1 & 2 perpendicular b/c they are reciprocals with a sign change :)

lines 1 & 3 neither.. differet slopes and not reciprocals

lines 2 & 3 perpendicular b/c they are reciprocals with a sign change :)

6 0

2 years ago

The sum of three consecutive integers is 174174. what are the integers?

baherus [9]

58057, 58058, 58059 are the numbers!

6 0

3 years ago

Calculate the sample mean and sample variance for the following frequency distribution of heart rates for a sample of American a

spin [16.1K]

Answer:

$Mean = 68.9$

$s^2 =18.1$ --- Variance

Step-by-step explanation:

Given

$\begin{array}{cccccc}{Class} & {51-58} & {59-66} & {67-74} & {75-82} & {83-90} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}$

Solving (a): Calculate the mean.

The given data is a grouped data. So, first we calculate the class midpoint (x)

For 51 - 58.

$x = \frac{1}{2}(51+58) = \frac{1}{2}(109) = 54.5$

For 59 - 66

$x = \frac{1}{2}(59+66) = \frac{1}{2}(125) = 62.5$

For 67 - 74

$x = \frac{1}{2}(67+74) = \frac{1}{2}(141) = 70.5$

For 75 - 82

$x = \frac{1}{2}(75+82) = \frac{1}{2}(157) = 78.5$

For 83 - 90

$x = \frac{1}{2}(83+90) = \frac{1}{2}(173) = 86.5$

So, the table becomes:

$\begin{array}{cccccc}{x} & {54.5} & {62.5} & {70.5} & {78.5} & {86.5} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}$

The mean is then calculated as:

$Mean = \frac{\sum fx}{\sum f}$

$Mean = \frac{54.5*4+62.5*3+70.5*11+78.5*13+86.5*4}{6+3+11+13+4}$

$Mean = \frac{2547.5}{37}$

$Mean = 68.9$ -- approximated

Solving (b): The sample variance:

This is calculated as:

$s^2 =\frac{\sum (x - \overline x)^2}{\sum f - 1}$

So, we have:

$s^2 =\frac{(54.5-68.9)^2+(62.5-68.9)^2+(70.5-68.9)^2+(78.5-68.9)^2+(86.5-68.9)^2}{37 - 1}$

$s^2 =\frac{652.8}{36}$

$s^2 =18.1$ -- approximated

5 0

2 years ago