105/2^9
Step-by-step explanation:
The probability of getting a head in a single toss
p=12
The probability of not getting a head in a single toss
q=1−12=12
Now, using Binomial theorem of probability,
The probability of getting exactly r=4 heads in total n=10 tosses
=10C4(1/2)4(1/2)10−4
=10×9×8×7/4! 1/2^4 1/2^6
=2^44⋅9⋅35/24(2^10)
=105/2^9
Answer:
- x = 8
- 12 = BD
- 23 = BE
- 13 = CE
Step-by-step explanation:
<u>We know that:</u>
- BD = 2x - 4
- DE = 2x - 3 - 2
- BE = 3x - 1
- CE = 2x - 3
<u>Solution:</u>
- (2x - 4) + (2x - 3 - 2) = 3x - 1
- => 2x - 4 + 2x - 3 - 2 = 3x - 1
- => 4x - 9 = 3x - 1
- => 4x - 3x = 9 - 1
- => x = 8
- => 2x - 4 = BD
- => 2(8) - 4 = BD
- => 16 - 4 = BD
- => 12 = BD
- => 3x - 1 = BE
- => 3(8) - 1 = BE
- => 24 - 1 = BE
- => 23 = BE
- => 2x - 3 = CE
- => 2(8) - 3 = CE
- => 16 - 3 = CE
- => 13 = CE
Hence, the answers are:
- x = 8
- 12 = BD
- 23 = BE
- 13 = CE
Probability of a tail for any on coin = 1/2
As the tosses of the 4 coins are independent of each other we multyiply the probs:-
P(4 tails) = 1/2 * 1/2*1/2*1/2 = 1/16
Answer:
x=1
Step-by-step explanation:
3(4x+1)=15
12x+3=15
12x=15-3
12x=12
x=12/12
x=1
Answer:
5
Step-by-step explanation:
1. in order to calculate all the required values, it needed to solve:

2. x≥5 means, that x∈[5;+∞), where beginnig is '5'.