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3 years ago

To find the area of a ____ multiply half the sum of the bases by the height

Mathematics

2 answers:

ss7ja [257]3 years ago

6 0

Answer:

trapezoid

Step-by-step explanation:

Oksana_A [137]3 years ago

4 0

To find the area of a triangle multiply half the sum of the bases by its height, i think?

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Solve for p: 6p + 6 = 13 + 5p

Ivan

Answer:

p equals 7

Step-by-step explanation:

6p + 6 = 13 + 5p

you subtract 6 from 13 and 5p from 6p

p = 7

7 0

2 years ago

Read 2 more answers

The Seniors at three high schools were surveyed about their plans after graduation. The following table shows the responses, cla

saw5 [17]

Answer:

E. 396/538

Step-by-step explanation:

The probability that the senior selected will not be from High School B given that the senior did not answer colege:

First, what's the probability of not having answered college? This will be out denominator.

P(not choosing college) = 244 + 106 + 188 = 538

Next, what's the probability that a senior in that category is not from HS B? Well, add the probabilities that the senior is in HS A or C:

P(senior is in HS A or C and answered not college) = 49 + 99 + 63 + 83 + 31 + 71 = 396

<u>Our answer is E. 396/538.</u>

7 0

3 years ago

Please help with all, I’ll mark brainliest as long as you tell me how you got that answer.

Mumz [18]

Answer:

function= 2nd,6th

not a function=1st,3rd,4th,5th

Step-by-step explanation:

because in graphing a function, there should only be one y for the x. 2 or more y's in one x is considered as not a function

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3 years ago

I need help on 11 and 12.

kvv77 [185]

I need help with this please respond rn

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2 years ago

Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real

adoni [48]

Step-by-step explanation

<h3>Prerequisites:</h3>

$b^2 - 4ac = 0 \Rightarrow 1 solution$

$b^2 - 4ac > 0 \Rightarrow 2 solutions$

$b^2 - 4ac < 0 \Rightarrow No\ real\ solutions$

----------------------------------------------------------------

$2x^2-7x-9 = 0$

$b^2 - 4ac$

$-7^2 - 4(2)(-9) = 121$

2 Solutions

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$x^2-4x+4 = 0$

$b^2 - 4ac$

$-4^2 - 4(1)(4) = 0$

1 Solution

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$4x^2-3x-1 = 0$

$b^2 - 4ac$

$-3^2 - 4(4)(-1) = 25$

2 Solutions

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$x^2-2x-8 = 0$

$b^2 - 4ac$

$-2^2 - 4(1)(-8) = 36$

2 Solutions

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$3x^2+5x+3 = 0$

$b^2 - 4ac$

$5^2 - 4(3)(3) = -11$

No Solutions

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3 0

3 years ago

Read 2 more answers