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vaieri [72.5K]
3 years ago
13

How much would $200 invested at 5% interest compounded monthly be worth after 9years? Round your answer to the nearest cent

Mathematics
1 answer:
Feliz [49]3 years ago
4 0

Answer:

$311.20

Step-by-step explanation:

Here we are required to use the Compound interest formula for finding the Amount at the end of 9th year

The formula is given as

A=P(1+\frac{r}{n})^{tn}

Where ,

A is the final amount

P is the initial amount = $200

r is the rate of interest = 5% annual = 0.05

n is the frequency of compounding in a year ( Here it is compounding monthly) = 12

t is the time period = 9

Now we substitute all these values in the formula and solve for A

A=200(1+\frac{0.05}{12})^{9\times 12}

A=200(1+0.00416)^{108}

A=200(1.00416)^{108}

A=200 \times 1.556

A=311.20

Hence the amount after 9 years will be $311.20

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How to solve this system of equal: x+y+z=1;x^2+y^2+z^2=1
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The function V(t)=1,000(1.06)^t models the value of an investment after t years. What does the ".06" represent in the function?
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