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weeeeeb [17]
2 years ago
8

Try your best I'll give first person crown ​

Mathematics
1 answer:
GrogVix [38]2 years ago
5 0

Answer:

i THINK its c

Step-by-step explanation:

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Line w is perpendicular to the line y = −x − 5 and passes through the point (−2, 4). What is the y-intercept of line w?
Aleksandr [31]

The slope of a line perpendicular to another is the negative reciprocal of the original.  The negative reciprocal of -1 is 1.  The equation will read:

y=x+b

To solve for the y-intercept (b), plug in the given values of x and y:

4=-2+b

<em>*Add 2 to both sides*</em>

D. 6


Hope this helps!!

7 0
3 years ago
Evaluate 10b + 3c, if b=3 and c = 11.
kozerog [31]

Answer:

63

Step-by-step explanation:

10 × 3 = 30

3× 11 = 33

30 + 33 = 63

4 0
2 years ago
A town has 300 residents in total, of which 5/6 are white/Caucasian Americans. How many white/Caucasian Americans reside in this
Neko [114]

Answer:

250

Step-by-step explanation:

300* 5/6 = 250

3 0
3 years ago
Read 2 more answers
Suppose after 2500 years an initial amount of 1000 grams of a radioactive substance has decayed to 75 grams. What is the half-li
krok68 [10]

Answer:

The correct answer is:

Between 600 and 700 years (B)

Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years

First, let us calculate the decay constant (k)

75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036

Next, let us calculate the half-life as follows:

\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2}  \approx 669\ years

Therefore the half-life is between 600 and 700 years

5 0
3 years ago
I need help please ASAP
grin007 [14]
I’m pretty sure it is the first one
6 0
3 years ago
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