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weeeeeb [17]
2 years ago
8

Try your best I'll give first person crown ​

Mathematics
1 answer:
GrogVix [38]2 years ago
5 0

Answer:

i THINK its c

Step-by-step explanation:

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Show that 4/9 - 1/6 = 5/18
ludmilkaskok [199]

Answer:

Step-by-step explanation:

4/9-1/6=5/18

5 0
3 years ago
Read 2 more answers
It takes Vanessa a half hour to walk to the library. She leaves her house at 5:00. What time does she get to the library?​
serg [7]
She gets to the library at 5:30. Half an hour is equal to 30 minutes, and if she leaves at 5:00, she will be there in thirty minutes.
4 0
1 year ago
1) 130<br> 2) 25<br> 3) 50<br> 4) 60
pickupchik [31]

2x+5x+5=180 so x has to be 25

3 0
3 years ago
Which equation describes the line with a slope of -3 that contains the point (2,4)?
Ilia_Sergeevich [38]

Answer: y = 2x - 11

Step-by-step explanation:

A linear equation has the following form.

y = a . x + b

where,

y: independent variable

a: slope

x: independent variable

b: y-intercept

The slope is 2, so a is 2. The ordered pair (4, -3) means that when x takes the value 4, y takes the value -3. We can replace these values in the general equation to find the y-intercept.

y = a . x + b

-3 = 2 . 4 + b

b = -11

The linear equation is

y = 2x - 11

8 0
2 years ago
Read 2 more answers
Find the work required to move an object in the force field F = e^x + y (1, 1, z) along the straight line from A(0, 0, 0) to B(-
DENIUS [597]

\vec F(x,y,z)=(e^x+y)(1,1,z)

is conservative if we can find a scalar function f such that \nabla f=\vec F. This would require

f_x=e^x+y

f_y=e^x+y

f_z=(e^x+y)z

Integrating both sides of the first equation wrt x gives

f(x,y,z)=e^x+xy+g(y,z)

Differentiating both sides of this wrt y gives

f_y=x+g_y=1\implies g_y=1-x\implies g(y,z)=y-xy+h(z)

but we assumed g was a function of y and z, independent of x. So there is no such f and \vec F is not conservative.

To find the work, first parameterize the path (call it C) by

\vec r(t)=(1-t)(0,0,0)+t(-4,5,-5)=(-4t,5t,-5t)

for 0\le t\le1. Then

\vec r'(t)=(-4,5,-5)

and the work is given by the line integral,

W=\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\int_0^1(e^{-4t}+5t,e^{-4t}+5t,-(e^{-4t}+5t)5t)\cdot(-4,5,-5)\,\mathrm dt

W=\displaystyle\int_0^1(125t^2+5t+(25t+1)e^{-4t})\,\mathrm dt=\boxed{\frac{2207}{48}-\frac{129}{16e^4}}

8 0
3 years ago
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