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lyudmila [28]
2 years ago
6

How many different ways are there to rearrange the letters of the word EXAM, if you don't care if the results is a recognizable

word
Mathematics
1 answer:
Vlada [557]2 years ago
6 0
In this case, all letters are unique.

Start by holding the first letter:
E - XAM
E - XMA
E - MAX
E - MXA
E - AXM
E - AMX
So there are 6 combinations here.

Repeat for all 4 letters.

6 x 4 = 24

This is same as 4x3x2x1.

For 3 unique characters, it is 3x2x1.
For 5 unique characters, it is 5x4x3x2x1
And so on...
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A(x_A;\ y_A);\ B(x_B;\ y_B)\\\\|AB|=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}
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3 years ago
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Afina-wow [57]

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