Answer:
Son's age is 14 and father's age is 38
Step-by-step explanation:
The question in English is
Ten years ago my son's age was 1\7 of the father's. Now his ages add up to 52. What is the son's age?
Let
x -----> son's age
y ----> father's age
we know that
------> equation A
-----> equation B
Solve the system by graphing
Remember that the solution of the system is the intersection point both graphs
The solution is the point (14,38)
see the attached figure
therefore
son's age is 14 and father's age is 38
350 ÷ 6 = 58.33
58.33 pounds of chocolate per hour
58.33 × 10 = 583.3
583.33 pounds of chocolate in 10 hours
Answer:
<h2>m∠EFG = 126°</h2><h2>m∠GFH = 54°</h2>
Step-by-step explanation:
If ∠EFG and ∠GFH are a linear pair, then m∠EFG + m∠GFH = 180°
(look at the picture).
We have
m∠EFG = 5n + 16
m∠GFH = 2n + 10
Substitute:
(5n + 16) + (2n + 10) = 180 <em>combine like terms</em>
(5n + 2n) + (16 + 10) = 180
7n + 26 = 180 <em>subtract 26 from both sides</em>
7n + 26 - 26 = 180 - 26
7n = 154 <em>divide both sides by 7</em>
7n/7 = 154/7
n = 22
Insert the value of n into expressions that specify angle measures:
m∠EFG = 5n + 16 → m∠EFG = 5(22) + 16 = 110 + 16 = 126°
m∠GFH = 2n + 10 → m∠GFH = 2(22) + 10 = 44 + 10 = 54°
Range is the value of y
f(x)=-x²+5
when x=-1, f(x)=-(-1)²+5=4
when x=2, f(x)=-(2)²+5=1
so 1<y≤4
the second piece: f(x)=2x-3
when x=2, f(x)=2(2)-3=1
when x=5, f(x)=2(5)-3=7
so 1≤y<7
union of the two parts of y: 1≤y<7
[1,7) is the answer.
Answer:
attached
Step-by-step explanation:
draw line pass (-12,0) and (0,3), solution is the shaded part
