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NeTakaya
3 years ago
5

The ages of three brothers are consecutive integers with a sum of 96. how old are the brothers?

Mathematics
1 answer:
Troyanec [42]3 years ago
8 0

consecutive integers have a difference of 1 between them

let the brothers have ages n , n + 1 and n + 2 thus

n + n + 1 + n + 2 = 96

3n + 3 = 96

subtract 3 from both sides of the equation

3n = 96 - 3 = 93

divide both sides by 3

n = \frac{93}{3} = 31

The ages are 31 , 32 and 33



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