47+ 30 is 77 so def is 77 and 103 is deg. and
H = 2f / (m+1)
[multiply by (m+1)]
h(m+1) = 2f
[divide by 2]
f = (h (m + 1)) / 2
3b / (b+2) = 12 / (b+2)
[multiply by (b+2)]
3b = 12
[divide by 3]
b = 4
3 / (6x + 1) / 2 = 8 / (x + 4) / 3
[multiply both denominators to mike one denominator]
3 / 8(6x+1) = 8 / 3(x+4)
[expand brackets]
3 / (48x + 8) = 8 / (3x + 12)
[multiply by (48x + 8)]
3 = 8(48x + 8) / (3x+12)
[multiply by (3x+12)]
3(3x +12) = 4(48x + 8)
[simplify]
9x + 36 = 192x + 32
173x = 4
x = 4 / 173
Answer:
C ( i think)
Step-by-step explanation:
Tan⁴x - sec⁴x = 1 - 2sec²x
tan²x = sec²x - 1
tan⁴x - sec⁴x = 1 - 2sec²x
(tan²x)² - sec⁴x = 1 - 2sec²x
(sec²x - 1)² - sec⁴x = 1 - 2sec²x
(sec²x)² - 2 * sec²x + 1 - sec⁴x = 1 - 2sec²x
sec⁴x - 2 sec²x + 1 - sec⁴x = 1 - 2sec²x
sec⁴x can be cancelled:
- 2 sec²x + 1 = 1 - 2sec²x
1 - 2sec²x = 1 - 2sec²x
Answer:
The surface area of Triangular base Prism = 3682 cm²
Step-by-step explanation:
Given in question as :
For a Triangular base prism ,
The base of prism (b) = 24 cm
The height of prism (l) = 29 cm
Each side length (s) = 37 cm
The height of base triangle ( h ) = 35 cm
Hence , we know that The surface area of Triangular base prism is
= (b×h) + (2×l×s) + (l×b)
= (24×35) + (2×29×37) + (29×24)
= (840) + (2146) + (696)
= 3682 cm²
Hence The surface area of Triangular base Prism is 3682 cm² Answer
