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Verdich [7]
3 years ago
12

suppose all of the points in the figure are equidistant. start with your compass point on point A. to create a perpindicular bis

ector of AE through point C, open the compass to point ?
Mathematics
1 answer:
VladimirAG [237]3 years ago
4 0
The best answer i think would get is C i hope im right
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What is two 2/3÷1 1/6
babunello [35]

Answer:

0.57142857142

Step-by-step explanation:

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3 years ago
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The parent function f(x) = x3 is transformed to g(x) = (x – 1)3 + 4. Identify the graph of g(x).
Dominik [7]

we have f(x)=x^3 which is a cubic function.

and =(x-1)^3+4.

from f(x) and g(x) we know that both are cubic and g(x) has shrink of 1 and up by 4 units in x axis .

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3 years ago
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Tickets to a concert cost $50 for each orchestra seat and $40 for each
Vsevolod [243]

Answer:

H. the number of orchestra seat is 900

Step-by-step explanation:

Step one:

let the number of orchestra seat be x

and balcony seat be y

cost of orchestra= $50 each

cost of balcony =$40 each

total tickets= 1500

x+y= 1500----------1

amount earned= $69000

50x+40y=69000--------2

The system of equation for the situation is

x+y= 1500----------1

50x+40y=69000--------2

from 1, x=1500-y

put this in equation 2

50(1500-y)+40y=69000

75000-50y+40y=69000

-10y=69000-75000

-10y=-6000

divide both sides by -10

y=-6000/-10

y=600

put y= 600 in equation 1

x+600= 1500

x=1500-600

x=900

6 0
3 years ago
Hey guys please help find the area
V125BC [204]

Answer:

70.15 ft²

Step-by-step explanation:

The figure consists of two adjacent equilateral triangles (all angles are 60 degrees and all outer edges are 9 ft).

If we focus on one of these equilateral triangles, we can get the final area by multiplying the area of that one triangle by 2.

The formula for the area of a triangle is (1/2)(base)(height).  Remembering to multiply this by 2, we get

area of figure = (base)(height)

                                             √3

                       = (9 ft)(9 ft)(--------) = (81 ft²)(1.732) = 70.15 ft²

                                               2

4 0
3 years ago
How do I find the values of these
skad [1K]
Since the triangles are similar, then 32 = x+7 those two angles are too
solve for "x"

now using proportions   \bf \cfrac{\textit{small triangle}}{\textit{large triangle}}\qquad \cfrac{JK}{18}=\cfrac{12}{12+10}

solve for JK

\bf \cfrac{\textit{small triangle}}{\textit{large triangle}}\qquad \cfrac{12}{12+10}=\cfrac{9}{9+KG}\implies 12(9+KG)=(22)9
\\\\\\
108+9KG=198

solve for KG

the scale factor of the perimeter of both triangles is just the same as the ratio of the sides, or \bf \cfrac{12}{12+10}

3 0
3 years ago
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