Question

How do I find the values of these

Answer 1

Since the triangles are similar, then 32 = x+7 those two angles are too
solve for "x"

now using proportions   $\bf \cfrac{\textit{small triangle}}{\textit{large triangle}}\qquad \cfrac{JK}{18}=\cfrac{12}{12+10}$

solve for JK

$\bf \cfrac{\textit{small triangle}}{\textit{large triangle}}\qquad \cfrac{12}{12+10}=\cfrac{9}{9+KG}\implies 12(9+KG)=(22)9 \\\\\\ 108+9KG=198$

solve for KG

the scale factor of the perimeter of both triangles is just the same as the ratio of the sides, or $\bf \cfrac{12}{12+10}$