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MatroZZZ [7]
4 years ago
6

Find the solution of the equation given below.7+(-5x) = -33​

Mathematics
1 answer:
omeli [17]4 years ago
4 0

Answer:

x = 8

Step-by-step explanation:

Given

7 + (- 5x) = - 33

Note that + (- ) = -

7 - 5x = - 33 ( subtract 7 from both sides )

- 5x = - 40 ( divide both sides by - 5 )

x = 8

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I have calculus problems that I need help with.
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a. Note that f(x)=x^ne^{-2x} is continuous for all x. If f(x) attains a maximum at x=3, then f'(3) = 0. Compute the derivative of f.

f'(x) = nx^{n-1} e^{-2x} - 2x^n e^{-2x}

Evaluate this at x=3 and solve for n.

n\cdot3^{n-1} e^{-6} - 2\cdot3^n e^{-6} = 0

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\dfrac n2 = \dfrac{3^n}{3^{n-1}}

\dfrac n2 = 3 \implies \boxed{n=6}

To ensure that a maximum is reached for this value of n, we need to check the sign of the second derivative at this critical point.

f(x) = x^6 e^{-2x} \\\\ \implies f'(x) = 6x^5 e^{-2x} - 2x^6 e^{-2x} \\\\ \implies f''(x) = 30x^4 e^{-2x} - 24x^5 e^{-2x} + 4x^6 e^{-2x} \\\\ \implies f''(3) = -\dfrac{486}{e^6} < 0

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b. When n=4, we have derivatives

f(x) = x^4 e^{-2x} \\\\ \implies f'(x) = 4x^3 e^{-2x} - 2x^4 e^{-2x} \\\\ \implies f''(x) = 12x^2 e^{-2x} - 16x^3e^{-2x} + 4x^4e^{-2x}

Inflection points can occur where the second derivative vanishes.

12x^2 e^{-2x} - 16x^3 e^{-2x} + 4x^4 e^{-2x} = 0

12x^2 - 16x^3 + 4x^4 = 0

4x^2 (3 - 4x + x^2) = 0

4x^2 (x - 3) (x - 1) = 0

Then we have three possible inflection points when x=0, x=1, or x=3.

To decide which are actually inflection points, check the sign of f'' in each of the intervals (-\infty,0), (0, 1), (1, 3), and (3,\infty). It's enough to check the sign of any test value of x from each interval.

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Many people enjoy challenging themselves by running in marathons. A marathon is a 26-mile race. The runners wear numbers that id
defon
We can start by rewriting the initial equation <span>x +10y=260 in order to express how y depends on x.
</span>10y=260-x
y=26-0.1x
This is a linear function ( it's a straight line). Linear functions have two intercepts, y and x.
To find x-intercept (also called zero of a function) we set y=0 and we solve for x.
0=26-0.1x
26=0.1x
x=260
This means that at x=260 our function has a value of 0. y(x) represents a distance from the school. This means that when y(x) is 0 our athlete reached school (finished the race), so this also answers your second question. The time it takes an athlete to finish the race is 260 minutes.
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<span>
</span>
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