All categories

3 years ago

Answer the 2 pictures please and thank you (":

Mathematics

1 answer:

trapecia [35]3 years ago

4 0

7/9 is 0.78 so .85 is greater so the day she sold the most boxes is Tuesday.

You might be interested in

If A=bh, and if b=12 and h=8, what does A equal?

Luda [366]

$A=bh, \ b=12, \ h=8, \\ \\ A= 12 \cdot 8= 96$

6 0

4 years ago

Read 2 more answers

Translate (in terms of x) then solve the algebraic equation. When the sum of a number and 2 is subtracted from 13 the result is

Diano4ka-milaya [45]

13 - (x+2) = 8
subtract 13 from both sides
-(x+2) = -5
divide by -1 to get rid of negative
(x+2) = 5
subtract 2 from both sides
x=3

7 0

3 years ago

One nanometer equals about

Orlov [11]

Answer:

$1\ \text{nanometer}=4\times 10^8$

Step-by-step explanation:

Given : One nanometer equals about 0.00000004 inches.

To find : When writing this decimal as a single-digit integer multiplied by a power of ten, the single digit integer is and the power of ten ?

Solution :

$1\ \text{nanometer}=0.00000004$

$1\ \text{nanometer}=\frac{00000004}{100000000}$

$1\ \text{nanometer}=4\times 10^8$

Therefore, the decimal as a single-digit integer multiplied by a power of ten is $1\ \text{nanometer}=4\times 10^8$

4 0

3 years ago

In a week Mike ran 8 km farther than Bill, while Pete ran

LUCKY_DIMON [66]

Answer:

12 km

Step-by-step explanation:

m = b + 8

p = 3b - 1

p = m + 15

p = m + 15....and m = b + 8....so we are gonna sub

p = b + 8 + 15

p = b + 23

b + 23 = 3b - 1

23 + 1 = 3b - b

24 = 2b

24/2 = b

b = 12 <==== Bill ran 12 km

m = b + 8

m = 12 + 8

m = 20 km....this is what mike ran

p = m + 15

p = 20 + 15

p = 35 km....this is what pete ran

7 0

4 years ago

Part 2: NO LINKS!! NOT MULTIPLE CHOICE! Please help me

Dmitry_Shevchenko [17]

Answer:

(see attachment for tree diagram)

$\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}$

$\textsf{P(Head) and P(3)}=\sf \dfrac{1}{2} \times \dfrac{1}{6}=\dfrac{1}{12}$

$\textsf{P(Tail) and P(even)}=\sf \dfrac{1}{2} \times \dfrac{3}{6}=\dfrac{3}{12}=\dfrac{1}{4}$

$\textsf{P(not 6)}=\sf 1-\textsf{P(6)}=1-\dfrac{1}{6}=\dfrac{5}{6}$

$\implies \textsf{P(Head) and P(not 6)}=\sf \dfrac{1}{2} \times \dfrac{5}{6}=\dfrac{5}{12}$

As the six-sided die does not have a side labelled "7", the probability of rolling a 7 is zero.

$\implies \textsf{P(Head) and P(7)}=\sf \dfrac{1}{2} \times 0=0$

7 0

2 years ago