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-BARSIC- [3]
3 years ago
14

On sunday, 15 family members of the crowe family met for dinner. they each received an equal amount of the meatloaf, which weigh

ed 13 pounds. how much meatloaf did each family member receive?
Mathematics
2 answers:
Delicious77 [7]3 years ago
4 0
13 divided by 15 people = 13÷15 which is 0.87 (rounded to 2 decimal places).
each member receives 0.87 pounds of meatloaf.
FromTheMoon [43]3 years ago
3 0
You do 13/15 = <span>0.86666666666
you can round it to one decimal which would be 0.9
or to two decimal places which would be 0.87

hope this helps you</span>
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What is - ( 2)^3?<br><br><br> Help please
Alex777 [14]
Answer is -8

-2x2x2:-8
5 0
3 years ago
Diego made a scale drawing of a theater. The scale of the drawing was 1 inch : 3 feet. The
Artyom0805 [142]

Answer:

The actual stage is 42 feet long

Step-by-step explanation:

Step 1

Determine the conversion factor as shown;

1 inch in the drawing represents 3 feet in the actual drawing

To convert a measurement in inches in the drawing to an actual measurement, we use a conversion factor of 3. In the same way, to convert a measurement in feet in the actual stage to the drawing measurement in inches, we use a conversion factor of (1/3).

Step 2

Convert 14 inches in the drawing to the actual measurement of the stage as follows;

Actual stage length=drawing length×conversion factor

where;

drawing length=14 inches

conversion factor=3

replacing;

Actual stage length=(14×3)=42 feet

The actual stage is 42 feet long

3 0
3 years ago
You purchase 5 pounds of apples and 2 pounds of oranges for $9.Your friend purchases 5 pounds of apples and 6 pounds of oranges
babymother [125]

Answer:

x = 1 and y = 2

Step-by-step explanation:

Let apples are represented by x

and let oranges are represented by y

You purchase 5 pounds of apples and 2 pounds of oranges for $9. This line in equation format can be written as:

5x + 2y = 9

Your friend purchases 5 pounds of apples and 6 pounds of oranges for $17.

This line in equation format can be written as:

5x + 6y = 17

Now we have two equations:

5x + 2y = 9 -> eq (i)

5x + 6y = 17 -> eq(ii)

We can solve these equations to find the value of x and y.

Subtracting eq(i) from eq(ii)

5x + 6y = 17

5x + 2y = 9

-     -         -

_________

0+4y= 8

=> 4y = 8

y= 8/4

y = 2

Now, putting value of y in eq (i)

5x + 2y = 9

5x +2(2) = 9

5x +4 = 9

5x = 9-4

5x = 5

x = 1

so, x = 1 and y = 2

8 0
3 years ago
in a standard casino dice game the roller wins on the first roll if he rolls a sum of 7 or 11. what is the probability of winnin
Alborosie

<u>Answer-</u>

<em>The probability of winning on the first roll is </em><em>0.22</em>

<u>Solution-</u>

As in the game of casino, two dice are rolled simultaneously.

So the sample space would be,

|S|=6^2=36

Let E be the event such that the sum of two numbers are 7, so

E = {(1,6), (2,5), (3,4), (4,3), (5,2), (6,1)}

|E|=56

\therefore P(E)=\dfrac{|E|}{|S|}=\dfrac{6}{36}

Let F be the event such that the sum of two numbers are 11, so

F = {(6,5), (5,6)}

|F|=2

\therefore P(F)=\dfrac{|F|}{|S|}=\dfrac{2}{36}

Now,

P(\text{sum is 7 or 11)}=P(E\ \cup\ F)=P(E)+P(F)=\dfrac{6}{36}+\dfrac{2}{36}=\dfrac{8}{36}=\dfrac{2}{9}=0.22

8 0
4 years ago
M is the midpoint of AN, A has coordinates
maksim [4K]

Step-by-step explanation:

According to Question , M is the midpoint of AN, A has coordinates (-7,4), and M has coordinates (-4, -1).

<u>Figure</u><u> </u><u>:</u><u>-</u>

\setlength{\unitlength}{1 cm}\begin{picture}(20,12) \put(4,0.2){\line(0,-1){0.4}}\put(1,0){\line(1,0){6}} \put(3.8,-0.6){$\bf M(-4,-1) $} \put(1,-0.6){$\bf A (-7,4)$}   \put(6.8,-0.6){$\bf N(x,y)$} \end{picture}

Let the coordinates of N be ( x , y )

Now , according to Midpoint Formula , the midpoint of points say A(x , y) and B (x' , y') is given by ,

\boxed{\blue{ \bf Midpoint =\bigg( \dfrac{x+x'}{2} , \dfrac{y+y'}{2} \bigg) }}

<u>On</u><u> </u><u>using</u><u> </u><u>this</u><u> </u><u>formula</u><u> </u><u>,</u><u> </u>

=> Midpoint = \bigg( \dfrac{x+x'}{2} , \dfrac{y+y'}{2} \bigg)  \\ \\ => (-4, 1) = \bigg( \dfrac{x -7 }{2} , \dfrac{y + 4 }{2}\bigg) \\ \\ => -4 = \dfrac{x-7}{2} \\\\ => x - 7 = -8 \\\\ => x = 7 -8 \\\\ \boxed{\red{\sf=> x = -1 }} \\\\ => \dfrac{y+4}{2}=-1 \\\\=> y +4 = -2 \\ \\ y = -4-2 \\\\\boxed{\red{\sf=> y = -6 }}

8 0
3 years ago
Read 2 more answers
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