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Anton [14]
3 years ago
6

Richard walks every day for exercise at a rate of 1 kilometer every 12 min. At this rate ,how many meters can Richard walk in a

hour? please helppppppp
Mathematics
2 answers:
Anna71 [15]3 years ago
8 0

Answer: He can walk 5000 meters in one hour.

Step-by-step explanation:

According to the question,

\text{ The distance he covered in 12 minutes }=\text{ 1 km}

\text{ The distance he covered in 60 minutes }=\text{ 5 km}

\text{ The distance he covered in 1 hour }=\text{ 5 km}

Now, 1 km = 1000 meters,

\implies \text{ The distance he covered in 1 hour }=\text{ 5000 m}

garik1379 [7]3 years ago
3 0
60 minutes in an hour
60÷12=5
1,000 meter in 1 km
5×1=5
5×1000=5000
therefore, 5000 meters
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When calculating probability what value is does the numerator represent and what value does the
andrew-mc [135]

Answer:

Numerator represents number of ways achieving success.

Denominator represents total number of outcomes.

Step-by-step explanation:

P = \frac{number of succes events}{number of total events}

4 0
3 years ago
Answer any problem and I will be happy <br> (30) pts
KatRina [158]
Problem 4

c = speed of current
p = paddling speed in still water

Against current:
speed = p-c (start with paddling speed and subtract off current's speed)
speed = 2 (given)
p-c = 2
p = 2+c

With the current
speed = p+c (now the current is speeding things up, so we add on c)
speed = 3 (given)
p+c = 3
2+c+c = 3 ... plug in p = 2+c; solve for c
2+2c = 3
2+2c-2 = 3-2
2c = 1
c = 1/2
c = 0.5

Since c = 0.5, we can use this to find p
p = 2+c
p = 2+0.5
p = 2.5

So,
The speed of the river current is 0.5 mph
Rita's paddling speed in still water is 2.5 mph

==================================================

Problem 5

Terms to know:
headwind = wind that slows the plane down (wind is coming from the head of the plane flowing in the opposite direction of the plane's intended direction)
tailwind = wind that speeds the plane up (wind is coming from the tail of the plane flowing in the same direction of the plane's intended direction)

d = distance = 255 miles
p = speed of plane in still air
w = speed of wind

Against the wind (headwind), the plane travels 1.7 hours at some speed p-w. We start with the plane's speed in still air (p) and subtract off the wind speed because the wind is slowing the plane down. So the first equation is
(p-w)*1.7 = 255
since the plane travels 255 miles
I'm using the formula d = r*t
d = distance
r = rate or speed
t = time

Divide both sides of (p-w)*1.7 = 255 by 1.7 and we get p-w = 150
Then add w to both sides and we have p = 150+w

Similarly, the second equation is 
(p+w)*1.5 = 255
since the tailwind speeds the plane up from p to p+w, the time is 1.5 hrs and the distance is the same (255 mi)

Plug the equation p = 150+w into the second equation
(p+w)*1.5 = 255
(150+w+w)*1.5 = 255
(150+2w)*1.5 = 255
150*1.5+2w*1.5 = 255
225+3w = 255
225+3w-225 = 255-225
3w = 30
3w/3 = 30/3
w = 10

Use w = 10 to find p
p = 150+w
p = 150+10
p = 160

So,
wind speed = 10 mph
speed of plane in still air = 160 mph
6 0
3 years ago
write a real world example that could be solved by using the inequality 4x+8≥32.then solve the inequality
V125BC [204]
Sally had 8 dollars right before she was paid for working 4 hours. Sally has at least 32 dollars now.
how much was she paid per hour?
4x + 8 \geqslant 32
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6 0
3 years ago
Zack and his dad baked some cupcakes for his class. They put 6 cups on each of 8 plates. How many cupcakes did they put on the p
kolezko [41]

Answer:

48 cupcakes were put on the plates.

Step-by-step explanation: 6 x 8 = 48

I hoped this answer helped you solve your problem!

Sincerely, iloveyouplease123ims

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%28fog%29%28%20-%205%29" id="TexFormula1" title="(fog)( - 5)" alt="(fog)( - 5)" align="absmidd
Xelga [282]
That should be the answer

8 0
3 years ago
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