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2 years ago

A circle has a diameter of

Mathematics

1 answer:

nignag [31]2 years ago

4 0

Answer:

Circumference = 50.24 units

Area = 200.96 units²

Determining the area of the circle:

The formula of finding the area of the circle is π(r)² or π(d/2)².

(Where "r" represents the radius and "d" represents the diameter)

In this case, we are given the diameter. Thus, we will use the formula π(d/2)². Simply substitute the diameter in the formula to determine the area of the circle.

⇒ π(D/2)² = Area of circle

⇒ π(16/2)² = Area of circle

⇒ π(8)² = Area of circle

⇒ π × 64 = Area of circle

[Exact form of pie: 22/7; Approx form of pie: 3.14]

⇒ Area of circle ≈ 3.14 × 64

⇒ Area of circle ≈ 200.96 units²

Determining the circumference of the circle:

The formula of finding the circumference of a circle is 2πr or πd.

(Where "r" is radius and "d" is diameter)

In this case, we are given the diameter. Thus, we will use the formula πd. Simply substitute the diameter in the formula to determine the circumference of the circle.

⇒ πd = Circumference of circle

⇒ π(16) = Circumference of circle

[Exact form of pie: 22/7; Approx form of pie: 3.14]

⇒ (3.14)(16) ≈ Circumference of circle

⇒ 50.24 units ≈ Circumference of circle

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PLEASE HELP!!!!!

Katena32 [7]

Answer:6018

Step-by-step explanation:

Given Sequence

$-282-266-250-234.....$

It represent an A.P. with

first term $a=-282$

common difference $d=16$

So sum of 51 term

$S_n=\frac{n}{2}[2a+(n-1)d]$

$S_{51}=\frac{51}{2}\times [2\times (-282)+(51-1)16]$

$S_{51}=\frac{51}{2}\times [-564+800]$

$S_{51}=\frac{51}{2}\times [236]$

$S_{51}=51\times 118$

$S_{51}=6018$

7 0

3 years ago

Lily goes car shopping and finds two cars. The first one burns fossil fuel, gasoline, that sells for $18,000. It will cost $100

Anna007 [38]

Answer:

Cost to buy and run the first car for 5 years=$24000

Cost to buy and run the second car for 5 years=$26000

I think we should buy the first car, because It is cheaper to buy and maintain

Step-by-step explanation:

first car:

Cost $18000 to buy

Cost $100 to maintain each month

5years =5 x 12=60months

Cost to maintain for 60months=100x60=$6000

First car cost to buy and run over the 5 year period=18000+6000=$24000

Second car:

It cost $22400 to buy

Cost $60 to maintain each month

5years=60months

Cost to maintain for 60months is 60 x 60=$3600

Cost to buy and run over the second car for 5years is 22400+3600=$26000

4 0

4 years ago

Quiz 3

andrezito [222]

It is 2x+8!!!!!!! I’m pretty sure

4 0

3 years ago

What is the side length of the eectagkes

dedylja [7]

1. 5 in and 1/3 in: Area = 5/3 in^2

2. 5 in and 4/3 in: Area= 20/3 in^2

3. 5/2 in and 4/3 in: Area=10/3 in^2

4. 7/6 in and 6/7 in: Area = 1 in^2

Step-by-step explanation:

1. 5 in and 1/3 in

Here,

$Let\\l=5\\w=\frac{1}{3}\\Area=l*w\\=5*\frac{1}{3}\\=\frac{5}{3}\ in^2$

2. 5 in and 4/3 in

Here,

$l= 5\ in\\w=\frac{4}{3}\ in\\Area=l*w\\=5*\frac{4}{3}\\=\frac{20}{3}\ in^2$

3. 5/2 in and 4/3 in

$let\\l=\frac{5}{2}\\w=\frac{4}{3}\\Area= \frac{5}{2}*\frac{4}{3}\\=\frac{20}{6}=\frac{10}{3}\ in^2$

4. 7/6 in and 6/7 in

Let

$l=\frac{6}{7}\\w=\frac{7}{6}\\Area=l*w\\=\frac{6}{7}*\frac{7}{6}\\=1\ in^2$

Hence,

1. 5 in and 1/3 in: Area = 5/3 in^2

2. 5 in and 4/3 in: Area= 20/3 in^2

3. 5/2 in and 4/3 in: Area=10/3 in^2

4. 7/6 in and 6/7 in: Area = 1 in^2

Keywords: Rectangle, Area

Learn more about rectangles at:

#LearnwithBrainly

8 0

4 years ago

Please help. Is algebra. PLEASE HELP NO LINKS OR FILES

Alexandra [31]

It’s B. 7th degree monomial

8 0

3 years ago