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faltersainse [42]
3 years ago
10

On the playground, ¼ of the students are on the jungle gym and ⅓ of the students are playing kickball. What part of all the stud

ents on the playground is on the jungle gym or playing kickball? Show how you found you answer.
Mathematics
1 answer:
babunello [35]3 years ago
6 0
7/12 of people on the playground were on the jungle gym or playing kickball
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ZanzabumX [31]

Note the equal sign. What you do to one side, you do to the other.


Isolate the variable. Divide 4 from both sides


(-52)/4 = (4m)/4


m = -52/4


m = -13


-13 is your answer for m



hope this helps

8 0
3 years ago
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3 years ago
Use the following steps to prove that log b(xy)- log bx+ log by.
borishaifa [10]

Answer with Step-by-step explanation:

a.x=b^p

y=b^q

Taking both sides log

log x=plog b

Using identity:logx^y=ylogx

p=\frac{logx}{log b}=log_b x

Using identity:log_x y=\frac{log y}{log x}

log y=qlog b

q=\frac{log y}{log b}=log_b y

b.xy=b^pb^q

We know that

x^a\cdot x^b=x^{a+b}

Using identity

xy=b^{p+q}

c.log_b(xy)=log_b(b^{p+q})

log_b(xy)=(p+q)log_b b

Substitute the values then we get

log_b(xy)=(log_b x+log_b y)

By using log_b b=1

Hence, log_b(xy)=log_b x+log_b y

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3 years ago
Please help I'm so close to being done and I don't know how to do this!!! Pls give answer but show how to do it!!!
cestrela7 [59]

Answer:

  • 8y + 16

Step-by-step explanation:

The shaded area is the difference of the large and small squares.

<u>Area of large square:</u>

  • A(l) =  (y + 4)²

<u>Area of small square:</u>

  • A(s) = y²

<u>Shaded area:</u>

  • A = A(l) - A(s)
  • A = (y + 4)² - y² = y² + 8y + 16 - y² = 8y + 16

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3 years ago
Lamar is considering two loans.
Varvara68 [4.7K]

Answer:

a.

Loan I's increase was 0.03 percentage points greater than Loan H's

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4 years ago
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