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2 years ago

Please help! Not sure what the question is asking exactly and need this last problem done asap!

Mathematics

2 answers:

Diano4ka-milaya [45]2 years ago

7 0

Answer:

look at the photo..............

vaieri [72.5K]2 years ago

6 0

9514 1404 393

Answer:

log₅(21) = log₅(3) +log₅(7)

Step-by-step explanation:

The relevant relation is ...

log(ab) = log(a) +log(b)

where the logs have any consistent base.

Here, we have ,,,

ab = 21 = 3·7.

Then ...

log(21) = log(3) +log(7)

When the logs are to base 5, that becomes ...

log₅(21) = log₅(3) +log₅(7)

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Please I need help I'm bad at math

Aleonysh [2.5K]

I think the answer is -44n+2

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2 years ago

Read 2 more answers

Which of the following is a radical equation? X+5 - 12 x2 = 16 3+xV7-13 7x = 14

NemiM [27]

Answer:

3+x sqrt 7 -13 is a radical equation.

8 0

2 years ago

The stock of Company A lost $4.17 throughout the day and ended at a value of

Anit [1.1K]

Answer:

Step-by-step explanation:

After losing 4.17, it came down to 100.08, so the opening price was:

100.08 + 4.17 = 104.25

To find percentage decline, we find the ratio of the "change" (which is 4.17) divided by the opening (original) price, which is 104.25. Then we multiply that fraction by 100 to get our percentage decline.

So,

$\frac{4.17}{104.25}*100=4$

Thus, the

percentage decline = 4%

4 0

2 years ago

You bike 1 mile the first day of your training, 1.3 miles the second day, 1.9 miles the third day, and 3.1 miles the fourth d

JulsSmile [24]

Answer:

19.9 miles

Step-by-step explanation:

In this problem we have:

$d_1=1 mi$ is the distance travelled during the 1st day

$d_2=1.3 mi$ is the distance travelled during the 2nd day

$d_3=1.9 mi$ is the distance travelled during the 3rd day

$d_4=3.1 mi$ is the distance travelled during the 4th day

We notice that the difference between the distance travelled on the (n+1)-th day and the distance travelled on the n-th day doubles every day. In fact:

$d_2-d_1=0.3\\d_3-d_2=2\cdot 0.3 = 0.6\\d_4-d_3=2\cdot 0.6 = 1.2$

Which can be rewritten using the general formula:

$d_{n+1}-d_n=2(d_n-d_{n-1})$

This means that

$d_{n+1}=d_n+2(d_n-d_{n-1})$

By applying this formula recursively, we can find the 7th term, which is the distance travelled on the 7th day:

$d_1=1\\d_2=1.3\\d_3=1.9\\d_4=3.1\\d_5=3.1+2\cdot 1.2=5.5\\d_6=5.5+2\cdot 2.4=10.3\\d_7=10.3+2\cdot 4.8=19.9 mi$

So, the distance travelled on the 7th day is 19.9 miles.

7 0

3 years ago

One number is 4 more than another, and their sum is 60. What is the smaller number?

ivanzaharov [21]

According to your question, there are 2 unknown numbers mentioned. Let the 2 unknown numbers be represented by the variables x & y, then x is considered to be one of the numbers being more than y by the addition of 4, .ie. x = 4 + y --- (1) The sum of the 2 numbers is 60, i.e. x + y = 60 --- (2) To find the smaller number, we solve eqn (1) & (2) using the concept of substitution, i.e. substitute 4 + y for x in eqn (2), i.e. 4 + y + y = 60 4 + 2y = 60 2y = 60 - 4 2y = 56 y = 28 ...Ans. Recall that x is more than y by 4, then 28 is the smaller number.

5 0

3 years ago