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n200080 [17]
3 years ago
10

What is equal to three tenths 0.6 0.03 0.2 0.3 0.10

Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
5 0
0.03 is equal to three tenths

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Evaluate ƒ(x) when x = 10
AlladinOne [14]

Answer:

10f ?

Step-by-step explanation:

fx10

8 0
3 years ago
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Solve the system of equations using substitution y=x-1 and y=-2x+5
pav-90 [236]
Since the two equations equal y, set them equal to each other.

x-1=-2x+5

From there, solve for x.

First get x on one side, by using the addition property of equality.

x-1=-2x+5
3x-1=5

Isolate x by adding 1.
3x=6

Lastly get x all by itself by dividing each side by 3.
x=2

You can now substitute your x-value, 2, into one of the equations (or both, if you wish; either one will result in the same answer.)

y=x-1
y=2-1
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OR

y=-2x+5
y=-2(2)+5
y=-4+5
y=1

Final answer:
x=2 and y=1

Any questions or anything you would like me to clarify, feel free to ask :)
7 0
3 years ago
If i divide 3/4 with 2/5 what would the answer be​
Talja [164]

Answer:

The asnwer i fro 5/2 iss 2.5 and the other question is the answer is 1.3 is we add now is 3.8

Step-by-step explanation:

4 0
3 years ago
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What are RQS and TQS?
yaroslaw [1]

Answer:

m∠RQS = 72°

m∠TQS = 83°

Step-by-step explanation:

m∠RQS +m ∠TQS = m∠RQT

The two angles combine to make a larger angle

So

m∠RQS = (4x - 20)

m∠TQS = (3x + 14)

(4x - 20) + (3x + 14) = 155

Group the Xs and the constants

4x + 3x - 20 + 14 = 155

Combine like terms

7x - 6 = 155

Add 6 to both sides

7x = 161

Divide by 7 on both sides

x = 23

Check:

4(23) - 20 + 3(23) + 14 = 155

92 - 20 + 69 + 14 = 155

155 = 155

But we need to find m∠RQS and m∠TQS. So plug in x = 23 to the values.

m∠RQS = 4(23) - 20 = 72°

m∠TQS = 3(23) + 14 = 83°

Checking:

72 + 83 = 155

8 0
3 years ago
H2 + 7h + 10 = 0<br> Help please
Leni [432]

Answer:

-2, -5

Step-by-step explanation:

h2 + 7h + 10 = 0

h^2 +7h + 10 = 0

h^2 +2h +5h + 10 = 0

h(h+2) + 5(h+2) = 0

h+2 = 0 or h+5 = 0

h = -2 or h = -5

4 0
3 years ago
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