Step-by-step explanation:
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Answer:
B and E
Step-by-step explanation:
Step-by-step explanation:
1.


Therefore,

2.


Use the identity

We chose the negative value of the cosine because of the condition where cot y > 0. Otherwise, choosing the positive root will yield a negative cotangent value. Now that we know the sine and cosine of y, we can now solve for the tangent:

3. Recall that sec x = 1/cos x, therefore cos x = 5/6. Solving for sin x,

Solving for tan x:

Step-by-step explanation:
z^7/z^-14=21
z^21=21
Let the volume of the cylinder be V cubic meters, the diameter be d meters and the height be h meters.
Now we can write the formula for the volume as follows:

Rearranging the formula, the height becomes: