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3 years ago

14

Basher collected 4 1/3 basket of peaches and Orchard if each basket holds 21

1 answer:

miv72 [106K]3 years ago

6 0

To do this you times 3 by 4 and add it on to the numerator of the fraction, to turn it into a top heavy fraction:
3*4 = 12
1+12/3 = 13/3

Then you multiply the numerator by 21 to work out what 21 times the fraction is:
13*21/3 = 273/3

Then you can divide 273 by 3 to get the final answer:
273/3 = 91

He will have 91 peaches overall.
Hope this helps! :)

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This is a conditional probability exercise.

Let's name the events :

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In the exercise :

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We are looking for P(I/PT) :

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P(PT)= 0.0226 + 0.039975

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$P(I/PT)=\frac{0.0226}{0.062575} \\P(I/PT)=0.36116$

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