Because MK is a diameter, then angle L is a right angle. We already know that the measure of angle K is 50, so the measure of angle M has to be 40 because of the triangle angle-sum theorem. The rule for inscribed angles and the arcs they cut off is that the angle is half the measure of its intercepted arc or, likewise, the arc is twice the measure of the angle that cuts it off. Since arc LK is across from angle M and is cut off by angle M, then arc LK is twice the measure of angle M, and is 80. That's the same reason why angle L is 90; arc MK is a semi-circle, with a degree measure of 180, and angle L is half of that.

Arc LK = 80

5 0

2 years ago

P-21=34 P=34-21 P=13<br>What is the value of p?<br>

vredina [299]

Simplifying

P + -21 + -21 = 34 + -21

-21 + -21 + P = 34 + -21

Combine like terms: -21 + -21 = -42

-42 + P = 34 + -21

Combine like terms: 34 + -21 = 13

-42 + P = 13

Solving

-42 + P = 13

Solving for variable 'P'.

Move all terms containing P to the left, all other terms to the right.

Add '42' to each side of the equation.

-42 + 42 + P = 13 + 42

Combine like terms: -42 + 42 = 0

0 + P = 13 + 42

P = 13 + 42

Combine like terms: 13 + 42 = 55

P = 55

Simplifying

P = 55

3 0

2 years ago

F(x)=2x and g(x)=square root of x what is the domain of f(g(x))?

Dmitriy789 [7]

Answer:

$x\ge 0$

Step-by-step explanation:

The given functions are:

$f(x)=2x$

and

$g(x)=\sqrt{x}$

Now,

$f(g(x))=f(\sqrt{x} )$

$f(g(x))=2\sqrt{x}$

The domain refers to values of $x$ for which $f(g(x))=2\sqrt{x}$ is defined.

The expression under the radical sign must not be negative.

The domain is

$x\ge 0$

5 0

2 years ago