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3 years ago

6

mr.wilson saved 2,500 to buy airlines tickets he bought airline tickets for $372 each how much savings does mr.wilson after he b

uys the tickets

2 answers:

ozzi3 years ago

7 0

2,500 subtracted by 372 equals 2148. 2148 dollars is how much savings he has left.

adoni [48]3 years ago

6 0

I think he either has 2,128 or 2,148 left over

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How many fourths are in 7/8

Nutka1998 [239]

$\dfrac{7}{8} \div \dfrac{1}{4}=\dfrac{7}{8}\cdot4=\dfrac{7}{2}=3.5$

5 0

3 years ago

the lateral area of a cylinder is 325 pi in2 the radius is 13 in find the following Volume. surface area

Nesterboy [21]

Volume: 2112.5π
Surface Area: 663π

First, let's find the height of the cylinder. Using the formula for lateral surface area, 2*π*r*h:

2*π*13*h = 325π
(divide π by both sides)
26h = 325
h = 12.5 in.

Next, let's solve the surface area of the cylinder using the formula π*r²*h.

π * 13² * 12.5 = π * 169 * 12.5 = 2112.5π.

Next, let's solve the surface area using the formula 2πrh + 2πr².

(2 * π * 13 * 12.5) + (2 * π * 13²) = 325π + 338π = 663π.

5 0

3 years ago

For three consecutive years, Sam invested some money at the start of the year. The first year, he invested x dollars. The second

wariber [46]

To answer we let x be the amount of money that Sam invested during the first year.

Below are the expressions translated from the given word forms for the amount invested.

Sam:
2nd year : amount = 5x/2 - 2000
3rd year : amount = x/5 + 1000

The sum of money invested by Sam is:
x + (5x/2 - 2000) + (x/5 + 1000)

Similarly, we derive the expressions that we use for the amount that Sally invested.
Sally
1st year : amount = 3x/2 - 1000
2nd year : amount = 2x - 1500
3rd year : amount = x/4 + 1400

The total amount that Sally invested is,
total = (3x/2 - 1000) + (2x - 1500) + (x/4 + 1400)

Equating the two equations:
(x) + (5x/2 - 2000) + (x/5 + 1000) = (3x/2 - 1000) + (2x - 1500) + (x/4 + 1400)

Solving for x,
x = 2000
For Sally's investment in the third year:
amount = x/4 + 1400 = (2000/4 + 1400) = 1900

ANSWERS:
Sam's first year = $2000
Sally's third year = $1900

3 0

3 years ago

Explain how to write 50000 using exponents

Yakvenalex [24]

I think i need a bit more information but assuming if this is what you are looking for:

to write 50,000 in exponent form look for its multiples other than 1 and itself and then go from there.

This is what i general do, i pick a divisible number and keep dividing till i get to one.

50,000/2 = 25,000
25,000/5 = 5,000
5,000/10 = 500
500/10 = 50
50/10 = 5
5/5 = 1
so i divided by 2, 5,10, 10, 10, and 5 (three 10s, two 5s and one 2)

then i look if these numbers can be written in smaller divisible numbers (i.e. 10 is 2 and 5)

so 2, 5, (2,5), (2,5) ,(2,5), and 5 as you can see that cannot be divided into smaller numbers so we have thus five 5s and four 2s

therefore 50,000 = 5^5 x 2^4

hope this helps :P

(P.S. it is the best way i can explain online without a whole course on this)

3 0

2 years ago

1. The data given below includes data from 42 candies, and 7 of them are red. The company that makes the candy claims that 33%

jeyben [28]

Answer:

The 95% confidence interval for true proportion of red candies is (5%, 27%).

The true proportion of red candies made by the company is different from 33%.

Step-by-step explanation:

The hypothesis to determine whether the claim made by the candy company is correct or not is:

<em>H</em>₀: The true proportion of red candies made by the company is 33%, i.e. <em>p</em> = 0.33.

<em>Hₐ</em>: The true proportion of red candies made by the company is different from 33%, i.e. <em>p</em> ≠ 0.33.

A (1 - <em>α</em>)% confidence interval can be constructed to check this claim.

The decision rule is:

If the confidence interval consists the null value then the null hypothesis will not be rejected. Otherwise it will be rejected.

The (1 - <em>α</em>)% confidence interval for population proportion is:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

The information provided is:

<em>n</em> = 42

<em>X</em> = number of red candies = 7

Compute the sample proportion of candies that are red as follows:

$\hat p=\frac{X}{n}=\frac{7}{42}=0.167$

The critical value of <em>z</em> for 95% confidence level is:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

*Use a <em>z</em>-table for the critical value.

Compute the 95% confidence interval for true proportion of red candies as follows:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.167\pm 1.96\times \sqrt{\frac{0.167(1-0.167)}{42}}\\=0.16\pm0.1137\\=(0.0463, 0.2737)\\\approx(0.05, 0.27)$

The 95% confidence interval for true proportion of red candies is (5%, 27%).

The confidence interval does not contains the null value.

Thus, the null hypothesis will be rejected at 5% level of significance.

Conclusion:

The true proportion of red candies made by the company is different from 33%.

7 0

2 years ago