Answer: Option C.
if resistance increases, flow decreases.
Explanation:
if resistance increases, flow decreases describe Poiseuille's law because it explain the relationship between fluid flow and the viscosity of the fluid, length and width of the turning. The law describe fluid flow is related to length and radius of tubing and viscosity. Increase in resistance will result in decrease in flow rate because flow and resistance are reciprocally related in one way or the other.
Answer:
During the oxidation of glucose in the liver the malate aspartate shuttle system is used, therefore, two additional ATPs get generated at the step constituting glyceraldehyde-3-phosphate dehydrogenase.
On the other hand, in the brain, a cell uses the glycerol phosphate shuttle system, which generates two less number of ATPs. However, the remaining of the energetics for the number of ATP in both cases are similar.
Thus, the difference is based upon the kind of shuttle system used that leads to the production of 32 ATPs in liver cells and 30 ATPs in the brain cells.
The answer is. the plant doesn't need carbon dioxide hope this help
The high concentration of carbon dioxide it yields; the air breathed in is converted into h2co3 before it goes to the lungs to be exchanged with oxygen
Answer:
3/4 taster; 1/4 non-taster
The likelihood that their first child will be a taster: 75 %
Explanation:
Complete dominance occurs when a dominant gene variant or 'allele' completely masks the expression of the recessive allele in heterozygous individuals (i.e., individuals carrying one copy of the dominant allele and one copy of the recessive allele). In this case, both parents are heterozygous for a single gene trait (i.e., the ability to taste) which is ruled by complete dominance. In consequence, the expected phenotypic ratio in the progeny (F1) will be:
- Alleles: T (dominant taster allele); t (recessive non-taster allele)
- Parental cross: Tt x Tt
- Punnett Square from this cross:
T t
T TT Tt
t Tt tt
Expected F1 phenotypic ratio: 3/4 taster (i.e., 1/4 TT genotype + 1/2 genotype Tt = 3/4 or 75%); 1/4 non-taster (tt genotype = 1/4 or 25%). Moroever, the chance that the first child has the taster phenotype is 3/4 (75%).
