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3 years ago

8

Jordan traveled from Seattle to New York City. First, he flew 1,735 miles from Seattle to Chicago. Then he drove 673 miles from

Chicago to New York.
How many miles did Jordan travel from Seattle to New York?

A.
1,062 miles

B.
1,162 miles

C.
2,308 miles

D.
2,408 miles

2 answers:

Soloha48 [4]3 years ago

8 0

The answer in letter d because 1735 plus 673

BARSIC [14]3 years ago

7 0

The correct answer would be D because, 1,735 miles plus 673 miles would be 2,408

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a polygon of 100 sides has all possible drawn from a chosen vertex to the others. how many triangles are formed

Hoochie [10]

Answer:

98

Step-by-step explanation:

for a 4 sided polygon you can only draw one diagonal from one vertex so it forms 2 triangles.

For 5 sides you get 3 triangles

For 6 sides - 4

For 7 sides - 5

For 8 sides - 6

Looks like we get 2 less triangles than the number of sides in the polygon

Answer for 100 sides is 98 triangles.

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3 years ago

Which inequality represents this sentence? Seven times six is less than or equal to nine times five.

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the answer is D

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4 years ago

Afirm will break even (no profit and no loss) as long as revenue just equals cost. The value of x (the number of items produced

s2008m [1.1K]

Cost function, $C(x)=300+15x$

Revenue function, $R(x) = 30x$

Profit function, $P(x)=15x-300$

Break point $x=20$ .

Fixed cost $=$ $ $300$ .

Variable cost $=$ $ $15$ .

Price of item $=$ $ $30$ .

Let $x$ be the number of items produced and sold.

a) Cost function $=$ Fixed cost $+$ variable cost \times number of items

So, $C(x)=300+15x$

b) Revenue $=$ Price of an item $\times$ number of items

So, $R(x) = 30x$

c) Profit $=$ Revenue $-$ Cost

$P(x)=R(x)-C(x)$

$P(x)=30x-300-15x$

$P(x)=15x-300$

d) <u>Break even point</u> $R(x)=C(x)$

$30x=300+15x$

$30x-15x=300$

$15x=300$

$x=20$ .

So, the product should be produced for $20$ or more items.

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2 years ago

10 normal six sided dice are thrown.Find the probability of obtaining at least 8 failuresif a success is 5 or 6.

erastova [34]

Answer:

0.2992 = 29.92% probability of obtaining at least 8 failures.

Step-by-step explanation:

For each dice, there are only two possible outcomes. Either a failure is obtained, or a success is obtained. Trials are independent, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A success is 5 or 6.

A dice has 6 sides, numbered 1 to 6. Since a success is 5 or 6, the other 4 numbers are failures, and the probability of failure is:

$p = \frac{4}{6} = 0.6667$

10 normal six sided dice are thrown.

This means that $n = 10$

Find the probability of obtaining at least 8 failures.

This is:

$P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10)$

So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{10,8}.(0.6667)^{8}.(0.3333)^{2} = 0.1951$

$P(X = 9) = C_{10,9}.(0.6667)^{9}.(0.3333)^{1} = 0.0867$

$P(X = 10) = C_{10,10}.(0.6667)^{10}.(0.3333)^{0} = 0.0174$

Then

$P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) = 0.1951 + 0.0867 + 0.0174 = 0.2992$

0.2992 = 29.92% probability of obtaining at least 8 failures.

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CaHeK987 [17]

Answer:

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Step-by-step explanation:

the distance from 5 and -4 is 9

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not a very good explanation but hope it helps

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3 years ago