Question

1. What is the value of x? Show all of your work.

Answer 1

The triangle is a right angled triangle with $B=90^o$. Now apply Pythagoras theorem,

$hypotenuse^2=opposite^2 + adjacent^2$

$AB^2+BC^2=AC^2\\ x^2+6^2=\sqrt{117}^2\\ x^2+36=117\\ x^2=81\\ x=9$

Thus, the value of $x=9\;cm$.

Answer 2

X^2 + 6^2 = {sqrt (117)}^2
x^2 + 36 = 117
Solve for x.
x^2 = 81
x = 9