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jenyasd209 [6]
3 years ago
5

What is the volume of this rectangular prism 7/5 CM by 5 cm and 7/2 cm

Mathematics
1 answer:
Step2247 [10]3 years ago
7 0

Answer:

V=\frac{49}{2}\ cm^3

or

V=24.5\ cm^3

Step-by-step explanation:

we know that

The volume of the rectangular prism is

V=LWH

where

L is the length

W is the width

H is the height

substitute the given values in the formula

V=(\frac{7}{5})(5)(\frac{7}{2})

V=\frac{245}{10}\ cm^3

Simplify

V=\frac{49}{2}\ cm^3 ---> fraction form

or

V=24.5\ cm^3 ----> decimal form

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4(c+2)<4c+10

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2 years ago
The sum of -3 times a number and 0.3 is at most 6.3. What are all the possible
densk [106]

Answer:

Step-by-step explanation:

Lets write an equation for this :)

So, the sum of -3 times a number and 0.3

This would be : -3x +0.3

Is at most, 6.3

so, it is equal to, or less than 6.3

-3x +0.3 <u><</u> 6.3

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2 years ago
Question 15 of 20 :
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Answer:

the answer is A

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6 0
2 years ago
Can you help me with my math questions
GrogVix [38]

p^2+2(7)p+7^2=(p+7)^2


Justification:

Given:  p^2+14p+49


Split the middle term;

=p^2+7p+7p+49


Factor:

=p(p+7)+7(p+7)


=(p+7)(p+7)


=(p+7)^2


QUESTION 3a

The given expression for the area of the rectangle is  36x^2-12x+1.


This is equal to the indicated area which is 289\;in^2


This implies that


36x^2-12x+1=289


\Rightarrow (6x-1)^2=289


\Rightarrow (6x-1)(6x-1)=289


\Rightarrow l=(6x-1),w=(6x-1)



This implies that, the dimensions of the rectangle are equal;


Using the square root method, we obtain

\Rightarrow (6x-1)=\pm \sqrt{289}


\Rightarrow (6x-1)=\pm 17


\Rightarrow 6x=1\pm 17


\Rightarrow 6x=18 \:or\:6x=-16


\Rightarrow x=3 \:or\:x=-\frac{2}{3}

We discard the negative value.

The side length of this rectangle is


\Rightarrow l=(6(3)-1)=17,w=6(3)-1=17


QUESTION 3b

The given expression for the area of the rectangle is  25x^2-50x+25.


This is equal to the indicated area which is 1225\;in^2


This implies that


25x^2-50x+25=1225


25(x^2-2x+1)=1225


(5(x-1))^2=35^2


5(x-1)5(x-1)=49


\Rightarrow l=5(x-1),w=5(x-1)



This implies that, the dimensions of the rectangle are equal;


Using the square root method, we obtain

\Rightarrow 5(x-1)=\pm \sqrt{1225}


\Rightarrow 5(x-1)=\pm 35


\Rightarrow x=1\pm 7


\Rightarrow x=8 \:or\:x=-6

We discard the negative value.

The side length of this rectangle is


\Rightarrow l=5(8-1)=35,w=5(8-1)=35



QUESTION 3c

The given expression for the area of the rectangle is  49x^2-56x+16.


This is equal to the indicated area which is 289\;in^2


This implies that


49x^2-56x+16=289




(7x-4)^2=289


(7x-4)(7x-4)=289



\Rightarrow l=(7x-4),w=(7x-4)


Applying the laws of indices gives;


(7x-4)^2=17^2


This implies that;

7x-4=17


7x=21


x=3in.


The side length of this rectangle is


\Rightarrow l=7(3)-4=17\:in.,w=7(3)-4=17\:in.


Dont forget that the square is also a rectangle.





5 0
3 years ago
Read 2 more answers
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