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jenyasd209 [6]
3 years ago
5

What is the volume of this rectangular prism 7/5 CM by 5 cm and 7/2 cm

Mathematics
1 answer:
Step2247 [10]3 years ago
7 0

Answer:

V=\frac{49}{2}\ cm^3

or

V=24.5\ cm^3

Step-by-step explanation:

we know that

The volume of the rectangular prism is

V=LWH

where

L is the length

W is the width

H is the height

substitute the given values in the formula

V=(\frac{7}{5})(5)(\frac{7}{2})

V=\frac{245}{10}\ cm^3

Simplify

V=\frac{49}{2}\ cm^3 ---> fraction form

or

V=24.5\ cm^3 ----> decimal form

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attashe74 [19]

Answer:

(a) The probability of more than one death in a corps in a year is 0.1252.

(b) The probability of no deaths in a corps over 7 years is 0.0130.

Step-by-step explanation:

Let <em>X</em> = number of soldiers killed by horse kicks in 1 year.

The random variable X\sim Poisson(\lambda = 0.62).

The probability function of a Poisson distribution is:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...

(a)

Compute the probability of more than one death in a corps in a year as follows:

P (X > 1) = 1 - P (X ≤ 1)

             = 1 - P (X = 0) - P (X = 1)

             =1-\frac{e^{-0.62}(0.62)^{0}}{0!}-\frac{e^{-0.62}(0.62)^{1}}{1!}\\=1-0.54335-0.33144\\=0.12521\\\approx0.1252

Thus, the probability of more than one death in a corps in a year is 0.1252.

(b)

The average deaths over 7 year period is: \lambda=7\times0.62=4.34

Compute the probability of no deaths in a corps over 7 years as follows:

P(X=0)=\frac{e^{-4.34}(4.34)^{0}}{0!}=0.01304\approx0.0130

Thus, the probability of no deaths in a corps over 7 years is 0.0130.

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3 years ago
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Answer:

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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First, solve each parenthesis

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mr_godi [17]

Answer:

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Step-by-step explanation:


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