All categories

2 years ago

Find circumference of circle 6m

Mathematics

1 answer:

nordsb [41]2 years ago

4 0

The circumference of the circle: $C_O=2\pi r$

r = 6m

subtitute

$C_O=2\pi\cdot6m=12\pi\ m$

You might be interested in

(x^2+3x-7)(2x-5) write in standard form

Gnoma [55]

Hi there!
The question is asking us to simplify the expression (x² + 3x - 7)(2x - 5) and write the answer in standard form. Here is how you do that -
Original: (x² + 3x - 7)(2x - 5)
Break it apart - [(x² + 3x - 7)(2x)] + [(x² + 3x - 7)(-5)]
Simplify -
2x³ + 6x² - 14x - 5x² - 15x + 35
Now, combine like terms -
2x³ + x² - 29x + 35
Therefore, the answer to your query is 2x³ + x² - 29x + 35. Hope this helps!

7 0

3 years ago

You have a square(40 inches by 24 inches) and reduce it to create the smaller box of 10 inches by 6 inches. What is the scale fa

Gnoma [55]

Answer:

4 inches

Step-by-step explanation:

40/24=10/6

40/10=4

24/6=4

(40/24)/(4/4)=10/6

(10/6)(4/4)=10/24

3 0

2 years ago

Solve each quadratic equation. Show your work. 14. (2x – 1)(x + 7) = 0 15. x2 + 3x = 10 16. 4x2 = 100

andreyandreev [35.5K]

14. (2x - 1)(x + 7) = 0

Using the zero factor property, we know that either the first or second terms (or both) must be equal to 0 if their product is 0. We can set each term equal to 0 to find the solutions:

2x - 1 = 0
2x = 1
x = 1/2

x + 7 = 0
x = -7

15. $x^{2} +3x=10$

To solve this equation, you first need to set it equal to 0:

$x^{2} +3x=10 \\ x^{2} +3x-10 = 0$

Next, it can be factored:

$x^{2} +3x-10 = 0 \\ (x+5)(x-2)=0$

Finally, we can solve just like we did above:

x + 5 = 0
x = -5

x - 2 = 0
x = 2

16. $4x^2=100$

First, you can simplify by dividing each side by 4:

$4x^2=100 \\ x^2=25$

Now, set the equation equal to 0:

$x^2=25 \\ x^2-25=0$

Next, factor:

$x^2-25=0 \\ (x+5)(x-5)=0$

Finally, find the solutions:

x + 5 = 0
x = -5

x - 5 = 0
x = 5

6 0

3 years ago

Suppose the solutions of a homogeneous system of four linear equations in five unknowns are all multiples of one nonzero solutio

Akimi4 [234]

Consider a homogeneous machine of four linear equations in five unknowns are all multiples of 1 non-0 solution. Objective is to give an explanation for the gadget have an answer for each viable preference of constants on the proper facets of the equations.

Yes, it's miles true.

Consider the machine as Ax = 0. in which A is 4x5 matrix.

From given dim Nul A=1. Since, the rank theorem states that

The dimensions of the column space and the row space of a mxn matrix A are equal. This not unusual size, the rank of matrix A, additionally equals the number of pivot positions in A and satisfies the equation

rank A+ dim NulA = n

dim NulA =n- rank A

Rank A = 5 - dim Nul A

Rank A = 4

Thus, the measurement of dim Col A = rank A = five

And since Col A is a subspace of R^4, Col A = R^4.

So, every vector b in R^4 also in Col A, and Ax = b, has an answer for all b. Hence, the structures have an answer for every viable preference of constants on the right aspects of the equations.

8 0

2 years ago

Each equation given below describes a parabola. Which statement best compares their graphs?

kkurt [141]

The answer to this question is

Both Parabolas open to the right, and x= 3y2 is wider than x= 5y2.

(APEX)

8 0

3 years ago

Read 2 more answers