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horrorfan [7]
3 years ago
8

How do stem leaf charts work

Mathematics
2 answers:
Lyrx [107]3 years ago
8 0

Answer & Explanation:

A stem and leaf plot is used to organize data as they are collected. A stem and leaf plot looks something like a bar graph. Each number in the data is broken down into a stem and a leaf, thus the name. The stem of the number includes all but the last digit.

Alla [95]3 years ago
4 0
A Stem and Leaf Plot is a special table where each data value is split into a stem (the first digit or digits) and a "leaf" (usually the last digit)
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After 2 months of living at his new apartment, Henry had 2 cats. Six months later, Henry still had 2 cats. Which of the graphs b
Volgvan
In a graph, time is the independent variable, which means that it will usually be the x axis.

Since the time keeps increasing but the number if cats do not, I would think that it is a horizontal line.

Hope this helps!
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Determine whether the equation is exact. If it​ is, then solve it. e Superscript t Baseline (7 y minus 3 t )dt plus (2 plus 7 e
umka21 [38]

Answer:

F(t,y)=(2+7e^t)y+3(1-t)e^t +C

Step-by-step explanation:

You have the following differential equation:

e^t(7y-3t)dt+(2+7e^t)dy=0

This equation can be written as:

Mdt+Ndy=0

where

M=e^t(7y-3t)\\\\N=(2+7e^t)

If the differential equation is exact, it is necessary the following:

\frac{\partial M}{\partial y}=\frac{\partial N}{\partial t}

Then, you evaluate the partial derivatives:

\frac{\partial M}{\partial y}=\frac{\partial}{\partial t}e^t(7y-3t)\\\\\frac{\partial M}{\partial t}=7e^t\\\\\frac{\partial N}{\partial t}=\frac{\partial}{\partial t}(2+7e^t)\\\\\frac{\partial N}{\partial t}=7e^t\\\\\frac{\partial M}{\partial t} = \frac{\partial N}{\partial t}

The partial derivatives are equal, then, the differential equation is exact.

In order to obtain the solution of the equation you first integrate M or N:

F(t,y)=\int N \partial y = (2 +7e^t)y+g(t)        (1)

Next, you derive the last equation respect to t:

\frac{\partial F(t,y)}{\partial t}=7ye^t+g'(t)

however, the last derivative must be equal to M. From there you can calculate g(t):

\frac{\partial F(t,y)}{\partial t}=M=(7y-3t)e^t=7ye^t+g'(t)\\\\g'(t)=-3te^t\\\\g(t)=-3\int te^tdt=-3[te^t-\int e^tdt]=-3[te^t-e^t]

Hence, by replacing g(t) in the expression (1) for F(t,y) you obtain:

F(t,y)=(2+7e^t)y+3(1-t)e^t +C

where C is the constant of integration

8 0
4 years ago
Please answer I need it asap. Please solve if you can!
tensa zangetsu [6.8K]

Answer: y=-0.54x+19.8

Step-by-step explanation:

Because it is asking for a line, it cannot be the first option (which is a quadratic) or the fourth option (which is an exponential).

This leaves us with the second and third options.

Since the line will have a negative slope (as the data is decreasing), this means that the only viable option is y=-0.54x+19.8.

7 0
2 years ago
The shaded portion of the bar model in Part A shows 38. What percent is equivalent to 38? Enter the correct answer in the box.
nordsb [41]

Question:

The shaded portion of the bar model in Part A shows 3/8. What percent is equivalent to 3/8? Enter the correct answer in the box.

Answer:

The equivalent is 37.5%

Step-by-step explanation:

Given

\frac{3}{8}

Required

The equivalent

<em>The model is not shown, but the question can still be solved.</em>

We have:

\frac{3}{8}

Multiply by 100%

\frac{3}{8} = \frac{3}{8} * 100\%

\frac{3}{8} = 0.375 * 100\%

\frac{3}{8} = 37.5\%

8 0
3 years ago
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