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3 years ago

7

A lunar day is in duration. hints a lunar day is in duration. 24 hours 12 hours 48 hours 24 hours and 50 m

inutes 12 hours and 25 minutes

1 answer:

soldi70 [24.7K]3 years ago

8 0

A lunar day is 24 hours and 50 minutes in duration.

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Part 3: Write the equation of and graph an ellipse.

tensa zangetsu [6.8K]

Answer:

Step-by-step explanation:

The center is halfway between vertices, at (4, -6).

It is also halfway between foci.

:::::

The vertices are vertically aligned, so the parabola is vertical.

General equation for a vertical ellipse:

(y-k)²/a² + (x-h)²/b² = 1

with

center (h,k)

vertices (h,k±a)

co-vertices (h±b,k)

foci (h,k±c), c² = a²-b²

Apply your data and solve for h, k, a, and b.

center (h,k) = (4, -6)

h = 4

k = -6

vertices (4,-6±a) = (4,-6±9)

a = 9

foci (4,-6±c) = (4,-6±5√2)

b² = a² - c² = 9² - (5√2)² = 31

b = √31

The equation becomes

(y+6)²/81 + (x-4)²/31 = 1

:::::

length of major axis = 2a = 18

length of minor axis = 2b = 2√31

8 0

2 years ago

1. In this figure, line m is parallel to line n, and p is a

mariarad [96]

Answer:

4

Step-by-step explanation:

picture attached as explanation

We can see through alternate interior and exterior angles, corresponding angles, and vertical angles what the measures are.

4 0

3 years ago

Ali has 41 miles remaining after 32 minutes of driving how many miles over remaining after 40 minutes of driving with the slope

algol [13]

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8 0

3 years ago

Trinh is serving 112 people cake , 5/8ths are getting chocolate how many people will get carrot ?

Novay_Z [31]

Hey!

If 112 people are getting cake and 5/8 are getting chocolate, that means the remaining will get chocolate.

8/8 - 5/8 = 3/8

3/8 are getting chocolate. You have to find 3/8 of 112.

3/8 × 112 = 336/8 = 42

42 people are getting carrot cake

:)

5 0

2 years ago

If two objects travel through space along two different curves, it’s often important to know whether they will collide. (Will a

galina1969 [7]

Answer:

<em>Both objects collide at t=3 in the point <9,9,9></em>

Step-by-step explanation:

<em>Collision Of Moving Objects </em>

Two objects can describe different trajectories in the space. Those trajectories can intersect in one or more points but it doesn't mean they collide. Collision occurs if they are in the same position at the same time. If we know the positions as a function of time of each object, we could try so find if, for a given time, they are in the same position.

The positions of two object are given as

$r1(t)=$

$r2(t)=$

Let's find out if there is at least one value of t that makes both positions to be the same. We can try by equating one of the three coordinates and testing if the value of t make both have the same x,y,z coordinate. Let's try equating the x-components of both

$t^2=4t-3$

Rearranging

$t^2-4t+3=0$

Factoring

$(t-1)(t-3)=0$

We found two solutions

$t=1,\ t=3$

for t=1 the x-coordinates are

$x1=t^2=1$

$x2=4t-3=1$

For t=3

$x1=t^2=9$

$x2=4t-3=9$

Now we'll test both values in the y-coordinates

$y1=7t-12$

$y2=t^2$

For t=1

$y1=-5$

$y2=1$

Thus they don't collide at t=1. Let's try t=3

$y1=7(3)-12=9$

$y2=3^2=9$

Now let's try the z-coordinate for t=3

$z1=t^2=9$

$z2=5t-6=9$

Since the three coordinates match, we can say both objects collide at t=3 in the point <9,9,9>

6 0

3 years ago