Answer:HMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMM
Step-by-step explanation:
never saw that before
So,
We'll just use A to represent both Jan and Mya's miles, since they ran the same number.
We have the equations:
1. Jan (J) = Mya (M)
2. Sara (S) = M - 8
3. 2A + S = 64
J = M
S = M - 8
We'll just use A to represent both J and M.
S = M - 8
We'll use Elimination by Substitution.
2A + A - 8 = 64
Collect Like Terms
3A - 8 = 64
Add 8 to both sides
3A = 72
Divide both sides by 3
A = 24
Since
A = J
and
A = M
and
J = M
then
J = 24
M = 24
Substitute
S = 24 - 8
S = 16
Check
24 + 24 + 16 = 64
64 = 64 This checks.
So,
J = 24
M = 24
S = 16
Answer:
C) x = ½
Step-by-step explanation:
Using the <em>Distributive Property</em> and combining like-terms will give you this:
-12 + 10x = 2x - 8
- 10x -10x
--------------------
-12 = -8x - 8
+ 8 +8
-------------
-4 = -8x [Divide by -8]
½ = x
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The answer is: " 2 :5 " ; or, write as: " 2/5 " .
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The ratio of 'girls' to 'all students' is: "2: 5 " ; or, write as: " 2/5 ".
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Explanation:
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Given: The ratio of boys to girls is: " 3:2 " .
Problem: Find the ratio of "girls" to "all students:
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Note: This ratio of "boys to girls", which is " 3 : 2 " ;
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→ can be expressed as " 3x: 2x" ;
in which the total number of students is: " 3x + 2x " = 5x " .
→ The total number of students is represented as: " 5x " .
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→ The ratio of "girls to boys" is: "2x : 3x" .
→ {that is; the "inverse" of the ratio of "boys to girls"} ;
→ {that is; the "inverse" of " 3x: 2x" } ; → which is: " 2x : 3x " .
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The ratio of "girls" to "all students" is: "2x : 5x " ; or " 2x/5x " ;
→ Both "x" values cancel ; {since: " x/x = 1 "} ;
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→ and we have the answer: " 2 :5 " ; or, write as: " 2/5 " .
_________________________________________________________
The ratio of 'girls' to 'all students' is: " 2 :5 " ; or, write as: " 2/5 ".
_________________________________________________________